Give step-by-step solution with explanation and final answer:" 25 1 Cylinders and Quadric Surfaces (13.6) a 1. Come te fin cmon of unc tc p orem (0) in ht des ek pps nh cin, she Kd oe Se va pe of hit: Chale or we sd bl ly ut oe apg so ht (Sn oe 30 gh of he cy etching vo 20 fe eto ses a ie yt igs i eae ox ht Ne
Question:
Give step-by-step solution with explanation and final answer:
" 25
1 Cylinders and Quadric Surfaces (13.6) a
1. Come te fin cmon of unc tc p
orem
(0) in ht des ek pps nh cin, she Kd oe
Se va pe of hit: Chale or we sd bl
ly ut oe apg so ht
(Sn oe 30 gh of he cy etching vo 20 fe
eto ses a ie yt igs i
eae ox ht Ne
This is AI generated Response.
Asked by: Test User 100249
Created at: 2025-05-19 09:50:17
Asked by: Test User 100249
Created at: 2025-05-19 09:50:17
Final Answer:
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Let's solve the problem step by step:
## **Given Equation:**
\[ 9y^2 + 4x^2 = 36 \]
---
### **(a) What kind of surface is this?**
**Step 1:** Notice that **z does not appear** in the equation.
- This means the equation is independent of z, so the surface is the same for every value of \( z \).
- Such a surface is called a **cylinder** (specifically, a "cylindrical surface" since it extends infinitely along the \( z \)-axis).
**Step 2:** The equation \( 9y^2 + 4x^2 = 36 \) is an **ellipse** in the \( xy \)-plane.
- Since it extends infinitely in the \( z \) direction, the surface is an **elliptic cylinder**.
**Final Answer (a):**
> The surface is an **elliptic cylinder**.
---
### **(b) Sketch the \( yx \)-trace of this surface.**
The \( yx \)-trace is just the curve \( 9y^2 + 4x^2 = 36 \) in the \( xy \)-plane.
**Step 1:** Rewrite in standard form:
\[
\frac{y^2}{4} + \frac{x^2}{9} = 1
\]
**Step 2:** Identify axes intercepts:
- For \( y \)-intercept (\( x = 0 \)): \( \frac{y^2}{4} = 1 \implies y^2 = 4 \implies y = \pm 2 \)
- For \( x \)-intercept (\( y = 0 \)): \( \frac{x^2}{9} = 1 \implies x^2 = 9 \implies x = \pm 3 \)
**Step 3:** Sketch
- Draw the \( x \)-axis and \( y \)-axis.
- Mark intercepts at \( (3, 0) \), \( (-3, 0) \), \( (0, 2) \), \( (0, -2) \).
- Draw an ellipse passing through these points.
**(Sketch example below):**
```
y
^
2 | *----*
| / \
| / \
| / \
-2 |*------------------*
+---------------------> x
-3 0 3
```
**Final Answer (b):**
> The \( yx \)-trace is an ellipse centered at the origin, with \( x \)-intercepts at \( x = \pm 3 \) and \( y \)-intercepts at \( y = \pm 2 \).
---
### **(c) Sketch a 3D graph of the surface**
**Step 1:** Extend the 2D ellipse in the \( z \)-direction.
- For every value of \( z \), the cross-section in the \( xy \)-plane is the same ellipse: \( 9y^2 + 4x^2 = 36 \).
**Step 2:** Draw axes \( x, y, z \).
- Draw the ellipse \( 9y^2 + 4x^2 = 36 \) in the \( xy \)-plane.
- Show this ellipse is present for every \( z \) value by drawing several ellipses stacked in the \( z \)-direction, forming a "tube" or cylinder.
**(Sketch example below):**
```
z
|
| ______
| / /
| / /
| / /
| /______/
+------------------- y
/
/
x
(Imagine the elliptical shape extending infinitely along the z-axis)
```
**Final Answer (c):**
> The surface is an elliptic cylinder with cross-sections \( 9y^2 + 4x^2 = 36 \) in the \( xy \)-plane, extending infinitely along the \( z \)-axis. The ellipse has \( x \)-intercepts at \( x = \pm 3 \), \( y \)-intercepts at \( y = \pm 2 \), for every value of \( z \).
---
**Summary Table:**
| Part | Answer |
|------|--------|
| (a) | Elliptic cylinder |
| (b) | Ellipse: \( x = \pm 3 \), \( y = \pm 2 \) |
| (c) | Elliptic cylinder in 3D, ellipse in \( xy \)-plane, extends along \( z \) |
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