Let's break down the reaction step by step. --- **Step 1: Analy the Starting Compound** The compound is a **diketone (actually, two ketone groups separated by two carbons), specifically **hexane-2,5-dione**. --- ## **Step 2: Reagent Analysis** The reagents are: 1. **1. LiAlH₄ (lithium aluminum hydride), -78°C** 2. **2. H₂O** **LiAlH₄** is a strong reducing agent, which can reduce: - Aldehydes, ketones → alcohols - Esters, carboxylic acids → primary alcohols But under these conditions, **LiAlH₄** will reduce both carbonyl groups (both ketones) to **alcohols**. --- ## **Step 3: Predicting the Product** - Each **C=O** (ketone group) will be reduced to a **CH–OH** (secondary alcohol) group. So, the product will be **hexane-2,5-diol**. **Structure of the product:** ``` OH OH | | CH3-CH-CH2-CH2-CH-CH3 ``` Or, in line structure, the two carbonyls are now alcohols: - The two ketones (at C2 and C5) become secondary alcohols. --- ## **Step 4: Drawing the Major Product** The structure will look like this (in condensed form): **HO–CH(CH₂CH₂)–CH(CH₂CH₂)–OH** But more clearly: **2,5-hexanediol** --- ## **Final Answer** **The major product is:** **2,5-hexanediol** **Structure:** ``` CH3–CH(OH)–CH2–CH2–CH(OH)–CH3 ``` Or a skeletal structure: ``` OH OH | | CH3–CH–CH2–CH2–CH–CH3 ``` **Explanation:** Both carbonyl groups (ketones) are reduced by LiAlH₄ to secondary alcohols. There are no carboxylic acids to consider, and side products are ignored as instructed.