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Give step-by-step solution with explanation and final answer:Build a circuit that receives three input bits A, B. C. The circuit should output the “majority” function. Namely, it should output 1 if two or more variables among 4, B.C’ are of value 1. Otherwise the circuit should output 0. Use the following steps in your solution: (a) present a truth table for the corresponding function, (b) write a corresponding algebraic expression, and (c) draw your circuit.

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Give step-by-step solution with explanation and final answer:Uploaded ImageBuild a circuit that receives three input bits A, B. C. The circuit should output the “majority” function. Namely, it should output 1 if two or more variables among 4, B.C’ are of value 1. Otherwise the circuit should output 0. Use the following steps in your solution: (a) present a truth table for the corresponding function, (b) write a corresponding algebraic expression, and (c) draw your circuit.

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Asked by: Rahul
Created at: 2026-02-28 03:13:48

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## Step-by-Step Solution ### (a) **Truth Table** Let's list all possible values for inputs \(A\), \(B\), \(C\) and the output: | A | B | C | Output (Maj) | |---|---|---|--------------| | | | | | | | | 1 | | | | 1 | | | | | 1 | 1 | 1 | | 1 | | | | | 1 | | 1 | 1 | | 1 | 1 | | 1 | | 1 | 1 | 1 | 1 | The output is 1 if **at least two inputs are 1**. --- ### (b) **Algebraic Expression** We need output 1 for cases where at least two variables are 1. Let's write the minterms: - \(A=1, B=1, C=\): \(A B \overline{C}\) - \(A=1, B=, C=1\): \(A \overline{B} C\) - \(A=, B=1, C=1\): \(\overline{A} B C\) - \(A=1, B=1, C=1\): \(A B C\) So, the sum of products is: \[ \text{Maj}(A,B,C) = AB + AC + BC \] This covers all cases where at least **two** variables are 1. --- ### (c) **Circuit Diagram** #### **Required Gates** - **AND gates** for \(AB\), \(AC\), \(BC\) - **OR gate** to combine them #### **Diagram** ``` A -------|&|----\ | | B ------- ( ) | |-----|≥1| C -------|&|----/ | |---- Output |-----|≥1| A -------|&|----/ | C ------- ``` Or, more traditionally: 1. **Three 2-input AND gates**: - First AND: inputs \(A, B\) → output \(AB\) - Second AND: inputs \(A, C\) → output \(AC\) - Third AND: inputs \(B, C\) → output \(BC\) 2. **One 3-input OR gate**: - Inputs: outputs of all three AND gates (\(AB, AC, BC\)) - Output: \(\text{Maj}(A,B,C)\) --- ## **Final Answer:** 1. **Truth Table:** See above. 2. **Algebraic Expression:** \[ \boxed{Maj(A,B,C) = AB + AC + BC} \] 3. **Circuit Diagram:** - Three 2-input AND gates (for \(AB\), \(AC\), \(BC\)) - One 3-input OR gate (to combine them) **(You may draw the circuit as described above for a complete solution.)**

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