Let's solve each problem step by step: --- ## **1. Resonance Forms for the Compound** The compound is a **phenyl group attached to a carbonyl (C=O), which is also attached to a double bond (vinyl group)**. ### **Step 1: Draw the Structure** The structure is: ``` O || Ph—C—CH=CH2 ``` Where **Ph = phenyl ring (benzene)**. ### **Step 2: Draw Resonance Forms** #### **Key Points:** - The carbonyl group (C=O) can participate in resonance with the phenyl ring. - The lone pairs on the oxygen and the double bonds in the ring can move. #### **Resonance Form 1 (original)** ``` O || Ph—C—CH=CH2 ``` #### **Resonance Form 2** - Move a lone pair from the oxygen to form a double bond with carbon and push the pi bond from C=O onto the oxygen: ``` O⁻ | Ph—C=CH—CH=CH2 | + ``` But this would break the aromaticity, so let’s focus on the conjugation between the carbonyl and the ring. #### **Resonance Form 3** - Move the double bond in the aromatic ring adjacent to the carbonyl towards the carbonyl, and push electrons from the C=O onto oxygen: ``` O⁻ | Ph—C=CH—CH=CH2 || ``` But let's be systematic. The resonance forms generally involve the aromatic ring and the carbonyl. #### **Let’s Number the Atoms for Clarity:** - Carbonyl carbon: 1 - Carbonyl oxygen: 2 - Phenyl: attached at carbon 1 #### **Resonance Form 2 (Phenyl donates electrons to carbonyl)** 1. Move the lone pair from the oxygen to form a double bond. 2. The pi bond from the benzene ring (ortho or para position) moves toward the carbonyl carbon. 3. The double bond in the benzene ring shifts. **Result:** ``` O⁻ | Ph—C=CH—CH=CH2 || ``` But let's draw it out with arrows. #### **Draw all five resonance forms:** ##### **Form 1: Original**  (Just for reference; see next for resonance arrows) ##### **Form 2: Oxygen donates lone pair** Move lone pair on O to make a double bond, push C=O pi bond to oxygen: ``` O⁻ | Ph—C=CH—CH=CH2 | + ``` ##### **Form 3: Benzene donates electrons** - Move electrons from the ortho position of benzene to the carbonyl carbon, move C=O electrons to O. - Formal charges: O gets -, ortho C gets +. ``` [Ph with positive charge at ortho, C1 with new double bond to O⁻, rest as before] ``` ##### **Form 4: Delocalization into benzene ring** - Move electrons further around the aromatic ring. ``` [Ph with positive charge at para, O⁻ at carbonyl, double bond at previous ortho] ``` ##### **Form 5: Delocalization further around the ring** - Continue moving electrons around the ring to meta position. ``` [Ph with positive at meta, O⁻ at carbonyl, with double bond at previous para] ``` #### **Curved Arrow Mechanism** 1. Lone pair on O to C=O bond, C=O bond to O (forms O⁻) 2. Pi bond in benzene to C1, C=O bond to O (forms O⁻ at O, + at benzene) 3. Move positive charge around benzene via resonance. #### **Summary Table** | Form | Description | |------|-------------| | 1 | Original structure | | 2 | Negative charge on O, C=O becomes C–O⁻ | | 3 | Benzene donates to C=O, O⁻, + on benzene | | 4 | Positive charge moves to para position | | 5 | Positive charge moves to meta position | --- ## **2. Compound with Aldehyde, Amide, Aromatic Ring (C₉H₉NO₂)** ### **Step-by-Step:** - **Aromatic ring**: benzene (C₆H₅) - **Aldehyde**: –CHO - **Amide**: –CONH₂ Combine these: - **Benzamide with an aldehyde group**: 4-formylbenzamide **Structure:** ``` O || C₆H₄—C—NH₂ | CHO (on para position) ``` **Line formula:** - p-Formylbenzamide (4-formylbenzamide) --- ## **3. Compound with Ketone, Aromatic Ring, Amine (C₉H₁₁NO)** ### **Step-by-Step:** - **Aromatic ring**: benzene (C₆H₅) - **Ketone**: –CO– - **Amine**: –NH₂ Combine: - **Aromatic ring with a ketone and amine substituent** - Example: 4-aminopropiophenone **Structure:** ``` O || C₆H₄—C—CH₃ | NH₂ (on para position) ``` **Line formula:** - p-Aminopropiophenone (4-aminopropiophenone) --- ### **Summary Table** | Q | Structure | Name | |---|-----------|------| | 2 | Benzene ring with –CONH₂ and –CHO groups | 4-Formylbenzamide | | 3 | Benzene ring with –COCH₃ and –NH₂ groups | 4-Aminopropiophenone | --- If you need **drawings or arrows** for the resonance, let me know!