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Asked by: Rahul
Created at: 2026-02-24 07:11:02
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## **Question 14: Which of (a)-(d) is the most stable conformation?**
### **Step 1: Analyze the Structures**
- Each structure is a chair conformation of cyclohexane with substituents: methyl (CH₃) and ethyl (CH₂CH₃).
- Stability in cyclohexane chairs: substituents are more stable in the equatorial position (less steric hindrance).
### **Step 2: Identify Substituent Positions**
Let's check each structure:
- **(a):** Both methyl and ethyl are equatorial.
- **(b):** Methyl is axial, ethyl is equatorial.
- **(c):** Methyl is equatorial, ethyl is axial.
- **(d):** Both methyl and ethyl are axial.
### **Step 3: Decide Most Stable**
- *Most stable:* Both large groups in equatorial positions (least steric strain).
- **Answer:** (a) is the most stable conformation.
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## **Question 15: Select the more stable chair conformation of trans-1,2-diisopropylcyclohexane.**
### **Step 1: Analyze the Molecule**
- **trans-1,2-diisopropylcyclohexane:** The two isopropyl groups are on carbons 1 and 2, and are trans to each other (one up, one down).
- Isopropyl is a large group, prefers equatorial position.
### **Step 2: Examine the Options**
You want **both isopropyl groups in equatorial positions** for maximum stability.
But, in a trans-1,2-disubstituted cyclohexane, you can only get one equatorial and one axial.
### **Step 3: Find the Correct Structure**
- Find the chair where both isopropyl groups are on adjacent carbons (1 and 2), one up (wedge) and one down (dash), and **both as equatorial as possible**.
- **Look for a chair where the large groups are anti to each other (trans), and at least one is equatorial.**
#### **Compare the options:**
- **A:** Both isopropyl groups are equatorial (not possible for trans-1,2).
- **B:** One up, one down, but both axial (least stable).
- **C:** One equatorial, one axial (correct for trans isomer).
- **D:** One equatorial, one axial.
#### **Check trans arrangement:**
- **C** is the correct chair conformation for trans-1,2-diisopropylcyclohexane with one equatorial and one axial isopropyl group.
### **Final Answer:**
**C** is the more stable chair conformation of trans-1,2-diisopropylcyclohexane.
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## **Summary Table**
| Q# | Answer | Reason |
|----|--------|------------------------------------------------------------------------------------------|
| 14 | (a) | Both large groups (methyl, ethyl) are equatorial (least steric strain, most stable) |
| 15 | (C) | Only possible to have one isopropyl equatorial in trans-1,2; C shows this arrangement |
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