Give step-by-step solution with explanation and final answer:1. Complete the following reactions by supplying the major product.
Cl,
EE
FeCl;
HNO,
—_—
H,SO,
Yel
a ——
0 AICI,
l
—
H,0,, H,SO,
H,SO
Oo +=
9
0 =e
AICI,
2. Explain why the Friedel-Crafts reaction shown below gives the following product ratios.
Ke -—
AICI,
0% 100%
Question:
Give step-by-step solution with explanation and final answer:1. Complete the following reactions by supplying the major product.
Cl,
EE
FeCl;
HNO,
—_—
H,SO,
Yel
a ——
0 AICI,
l
—
H,0,, H,SO,
H,SO
Oo +=
9
0 =e
AICI,
2. Explain why the Friedel-Crafts reaction shown below gives the following product ratios.
Ke -—
AICI,
0% 100%
This is AI generated Response.
Asked by: Rahul
Created at: 2026-02-21 08:30:52
Final Answer:
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---
## 1. Complete the following reactions by supplying the major product.
### **a. Benzene + Cl₂, FeCl₃**
This is an **electrophilic aromatic substitution** (halogenation).
**Major Product:**
- **Chlorobenzene**
**Reaction:**
```
Cl₂ / FeCl₃
C₆H₆ ------------> C₆H₅Cl
```

*Chlorobenzene structure*
---
### **b. Benzene + HNO₃, H₂SO₄**
This is **nitration**.
**Major Product:**
- **Nitrobenzene**
**Reaction:**
```
HNO₃ / H₂SO₄
C₆H₆ -------------> C₆H₅NO₂
```

*Nitrobenzene structure*
---
### **c. Benzene + tert-butyl chloride, AlCl₃**
This is a **Friedel-Crafts alkylation**.
**Major Product:**
- **tert-Butylbenzene**
**Reaction:**
```
(CH₃)₃CCl / AlCl₃
C₆H₆ -----------------> C₆H₅C(CH₃)₃
```

*tert-Butylbenzene structure*
---
### **d. Benzene + I₂, H₂O₂, H₂SO₄**
This is **iodination** of benzene (requires oxidant like H₂O₂).
**Major Product:**
- **Iodobenzene**
**Reaction:**
```
I₂, H₂O₂, H₂SO₄
C₆H₆ -----------------> C₆H₅I
```

*Iodobenzene structure*
---
### **e. Benzene + H₂SO₄ (heat)**
This is **sulfonation**.
**Major Product:**
- **Benzene sulfonic acid**
**Reaction:**
```
H₂SO₄ (heat)
C₆H₆ -----------------> C₆H₅SO₃H
```

*Benzene sulfonic acid structure*
---
### **f. Benzene + CH₃COCl, AlCl₃**
This is a **Friedel-Crafts acylation**.
**Major Product:**
- **Acetophenone**
**Reaction:**
```
CH₃COCl / AlCl₃
C₆H₆ ---------------> C₆H₅COCH₃
```

*Acetophenone structure*
---
## 2. Friedel-Crafts Product Ratio Explanation
**Reaction:**
- Benzene + tert-butyl chloride + AlCl₃ gives two possible products:
- Direct alkylation (tert-butylbenzene) = **%**
- Rearranged product (isopropylbenzene with methyl group, i.e., 1,1-dimethylpropylbenzene) = **100%**
**Explanation:**
- The alkyl chloride used is not tert-butyl chloride, but 1-chloro-2,2-dimethylpropane.
- When treated with AlCl₃, the initially formed carbocation can rearrange to a more stable tertiary carbocation.
- **Carbocation Rearrangement:** Hydride shift occurs, forming a more stable 3° carbocation.
- **Result:** The benzene attacks the rearranged, more stable carbocation, giving only the rearranged product.
- **No direct product** is formed because the rearrangement is very fast and highly favorable.
---
## **Summary Table**
| Reaction | Major Product | Structure/Name |
|----------------------------------|---------------------------|------------------------|
| Cl₂ / FeCl₃ | Chlorobenzene | C₆H₅Cl |
| HNO₃ / H₂SO₄ | Nitrobenzene | C₆H₅NO₂ |
| tert-Butyl Cl / AlCl₃ | tert-Butylbenzene | C₆H₅C(CH₃)₃ |
| I₂, H₂O₂ / H₂SO₄ | Iodobenzene | C₆H₅I |
| H₂SO₄ (heat) | Benzene sulfonic acid | C₆H₅SO₃H |
| CH₃COCl / AlCl₃ | Acetophenone | C₆H₅COCH₃ |
---
**Let me know if you need structures for each product or further clarification!**
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