Give step-by-step solution with explanation and final answer:v PartA In (Figure 1), 8= 44° Determine the coordinate direction angles of the force. Express your answers in degrees to tree significant figures and separated by commas. se om a B= | B Figure Tort z [ | Ferm
Question:
Give step-by-step solution with explanation and final answer:
v PartA
In (Figure 1), 8= 44°
Determine the coordinate direction angles of the force.
Express your answers in degrees to tree significant figures and separated by commas.
se om
a B= | B
Figure Tort
z [
|
Ferm
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Asked by: Rahul
Created at: 2026-02-18 04:18:47
Asked by: Rahul
Created at: 2026-02-18 04:18:47
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Let's break down the problem step by step:
## **Step 1: Write the Force Components**
Given:
- Magnitude of force \( F = 75 \) lb
- \( \theta = 44^\circ \) (angle with the \( z \)-axis)
- The projection of \( F \) on the \( xy \)-plane makes \( 45^\circ \) with the \( x \)-axis.
Let the coordinate direction angles be \( \alpha \) (with \( x \)), \( \beta \) (with \( y \)), and \( \gamma \) (with \( z \)).
### **Find the components:**
- The component along \( z \):
\( F_z = F \cos \theta \)
- The projection on \( xy \)-plane:
\( F_{xy} = F \sin \theta \)
- This projection makes \( 45^\circ \) with the \( x \)-axis:
- \( F_x = F_{xy} \cos 45^\circ \)
- \( F_y = F_{xy} \sin 45^\circ \)
Plug in the values:
- \( \cos 45^\circ = \sin 45^\circ = \frac{\sqrt{2}}{2} \)
- \( F_{xy} = 75 \sin 44^\circ \)
So:
\[
F_x = 75 \sin 44^\circ \cos 45^\circ
\]
\[
F_y = 75 \sin 44^\circ \sin 45^\circ
\]
\[
F_z = 75 \cos 44^\circ
\]
## **Step 2: Calculate the Components**
\[
\sin 44^\circ \approx .6947
\]
\[
\cos 44^\circ \approx .7193
\]
\[
\cos 45^\circ = \sin 45^\circ = .7071
\]
\[
F_{xy} = 75 \times .6947 = 52.1025
\]
\[
F_x = 52.1025 \times .7071 \approx 36.836
\]
\[
F_y = 52.1025 \times .7071 \approx 36.836
\]
\[
F_z = 75 \times .7193 \approx 53.4475
\]
## **Step 3: Find Direction Cosines**
Direction cosines:
\[
\cos \alpha = \frac{F_x}{F}
\]
\[
\cos \beta = \frac{F_y}{F}
\]
\[
\cos \gamma = \frac{F_z}{F}
\]
\[
\cos \alpha = \frac{36.836}{75} = .4911
\]
\[
\cos \beta = \frac{36.836}{75} = .4911
\]
\[
\cos \gamma = \frac{53.4475}{75} = .7126
\]
## **Step 4: Find the Angles**
\[
\alpha = \cos^{-1}(.4911) \approx 60.6^\circ
\]
\[
\beta = \cos^{-1}(.4911) \approx 60.6^\circ
\]
\[
\gamma = \cos^{-1}(.7126) \approx 44.6^\circ
\]
## **Step 5: Final Answers (to three significant figures)**
\[
\boxed{60.6^\circ,\ 60.6^\circ,\ 44.6^\circ}
\]
---
### **Summary Table**
| Angle | Value (degrees) |
|--------|----------------|
| \( \alpha \) | 60.6 |
| \( \beta \) | 60.6 |
| \( \gamma \) | 44.6 |
---
**Final Answer:**
\[
\boxed{60.6^\circ,\ 60.6^\circ,\ 44.6^\circ}
\]
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