# Step-by-Step Solution Let's break down the question and solve it step by step. --- ## 1. **Understanding the Task** The graph shows **Force (N)** vs **Time (s)**, and you are asked to find and record the **slope** of the line (with units and uncertainty). The slope here represents \(\frac{\Delta F}{\Delta t}\), or **change in force per change in time**. --- ## 2. **Extracting Data from the Graph** In the graph's legend/fit box, we see the linear fit equation: \[ \text{Linear:} \quad mt + b \] \[ m = -.436 \pm .003 \] \[ b = 2.957 \pm .043 \] Where: - \( m \) = **slope** (what we want) - \( b \) = y-intercept (not needed here) - Units: Since Force is in Newtons (N) and Time is in seconds (s), the slope's units are \( \frac{\text{N}}{\text{s}} \). --- ## 3. **Writing the Slope with Units and Uncertainty** So, the slope is: \[ m = -.436 \pm .003 \;\text{N/s} \] --- ## 4. **Final Boxed Answer** \[ \boxed{ \text{Slope} = -.436 \pm .003 \;\text{N/s} } \] - **Slope:** \(-.436\) - **Uncertainty:** \(\pm .003\) - **Units:** N/s (Newtons per second) --- ## 5. **Explanation** - The negative sign means force is **decreasing** over time. - The uncertainty (\(\pm .003\)) shows the confidence in the slope value calculated from the data. --- ### **Summary Table** | Quantity | Value | |------------------|-----------------------------| | Slope (\(m\)) | \(-.436 \pm .003~\text{N/s}\) | --- **Final Answer:** \[ \boxed{-.436 \pm .003~\text{N/s}} \]