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Asked by: Rahul
Created at: 2026-02-17 06:32:01
Final Answer:
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Let's solve the problem **step by step**:
---
## 1. **Understanding the Task**
You are asked to graph the **energy profile of butane** as it rotates about the C2–C3 bond, plotting energy (kcal/mol) vs. dihedral angle (degrees). Then, you are to draw the lowest energy conformer in wedge-dash notation.
---
## 2. **Butane Conformational Analysis**
- **Butane** (C₄H₁₀) has significant **conformational isomers** due to rotation about the C2–C3 bond.
- The main conformers are:
1. **Anti** (180°): Lowest energy (methyl groups farthest apart)
2. **Gauche** (60°, 300°): Higher energy (methyl groups closer)
3. **Eclipsed** (°, 120°, 240°, 360°): Highest energy (methyl groups overlap with each other or with hydrogens)
### **Approximate Energies (kcal/mol)**
- **Anti (180°)**: (reference, lowest)
- **Gauche (60°, 300°)**: ~.9
- **Eclipsed (°, 360°)**: ~5. (methyls eclipse each other)
- **Eclipsed (120°, 240°)**: ~3.6 (methyl eclipses a hydrogen)
---
## 3. **Plotting the Graph**
### **Label axes:**
- **Y-axis:** Energy (kcal/mol)
- **X-axis:** Dihedral angle about the C2–C3 bond (degrees)
### **Key points to plot:**
| Dihedral Angle (°) | Conformation | Energy (kcal/mol) |
|--------------------|------------------------|-------------------|
| | Eclipsed (Me–Me) | 5. |
| 60 | Gauche (Me–H) | .9 |
| 120 | Eclipsed (Me–H) | 3.6 |
| 180 | Anti (Me–Me staggered) | . |
| 240 | Eclipsed (Me–H) | 3.6 |
| 300 | Gauche (Me–H) | .9 |
| 360 | Eclipsed (Me–Me) | 5. |
**(Me = methyl, H = hydrogen)**
### **Shape of the curve:**
- Peaks at ° (and 360°) and 180° are minima.
- Local minima at 60° and 300° (gauche).
- Local maxima at 120° and 240° (eclipsed with H).
---
## 4. **Drawing the Graph**
You can sketch the plot using the table above. Here is a quick guide:
- Plot each point as above.
- Connect the dots smoothly to form a periodic curve.
- Label the X-axis and Y-axis.
- Title: "**Energy profile of butane by rotation about the C2–C3 bond**".
---
## 5. **Lowest Energy Conformer**
- **Anti conformation** (180°): methyl groups are staggered and opposite each other.
- **Wedge-dash drawing** for anti butane:
```
H H
\ /
C---C
/ \
CH3 CH3
```
- Or with dashed and wedged bonds (for C2 and C3):
```
H
\
C -- CH3
/ \
H3C H
```
- Both methyl groups (CH₃) are **anti** to each other.
---
## 6. **Final Answer**
### **Step-by-step summary:**
1. **Plot the energy profile** as described above, using the values for each angle.
2. **Label the graph** as "Energy profile of butane by rotation about the C2–C3 bond".
3. **Draw the lowest energy conformer** using the wedge-dash notation for the anti conformation (180°).
---
### **Example Graph (ASCII Art)**
```
Energy (kcal/mol)
|
| /\/\
| / \
| / \
|_______/ \_______
60 120 180 240 300 360
Dihedral angle (degrees)
```
---
### **Wedge-dash lowest energy conformer (Anti):**
```
H
\
C -- CH3
/ \
H3C H
```
---
**You can now sketch the graph and the conformer as described above on your paper!** Let me know if you need a digital drawing or further clarification.
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