Let's solve the problem step-by-step: ## Step 1: **Determine the Molecular Formula** Vinyl bromide: \( C_2H_3Br \) - 2 Carbons (C) - 3 Hydrogens (H) - 1 Bromine (Br) ## Step 2: **Determine the Structure** - "Vinyl" means an **ethene (ethylene) group** (\(CH_2=CH-\)) - One hydrogen replaced by bromine. So, the structure is: **H₂C=CHBr** ## Step 3: **Count Valence Electrons** - C: 4 valence electrons × 2 = **8** - H: 1 valence electron × 3 = **3** - Br: 7 valence electrons = **7** - **Total = 18 valence electrons** ## Step 4: **Draw the Skeleton** ``` H H \ / C = C \ Br ``` ## Step 5: **Add Bonds and Lone Pairs** - Each single bond = 2 electrons. - Each double bond = 4 electrons. **Bonds:** - 1 double bond between C and C (4 electrons) - 1 single bond from left C to H (2 electrons) - 1 single bond from left C to H (2 electrons) - 1 single bond from right C to H (2 electrons) - 1 single bond from right C to Br (2 electrons) So, all bonds: 4 + 2 + 2 + 2 + 2 = **12 electrons** used in bonds. **Remaining electrons**: 18 - 12 = **6 electrons** left (to place as lone pairs, usually on Br). **Br** is a halogen, usually has 3 lone pairs (6 electrons). ## Step 6: **Final Lewis Structure** ``` H H \ / C = C \ Br .. .. ``` - Each dot (:) represents a lone pair (3 pairs or 6 electrons on Br). ## **Final Answer:** Here is a text representation of the Lewis structure: ``` H H \ / C = C \ Br .. .. .. ``` - Br has three lone pairs. - All atoms have a complete octet (except H, which has 2 electrons). --- **Summary Table:** | Atom | Bonds | Lone Pairs | |------|-------|------------| | C(1) | 3 | | | C(2) | 3 | | | H | 1 | | | Br | 1 | 3 | --- **Lewis Structure for Vinyl Bromide (C₂H₃Br):** ``` H H \ / C = C \ Br : : : ``` (*Each ":" on Br represents a lone pair*)