Let's solve both parts (A and B) for the chalcone as shown in the **first image**. --- ## 2. (A) Chemical Equation to Synthesize the Chalcone ### Step 1: **Identify the Structure** The compound shown is a **chalcone derivative** with: - A 4-bromophenyl group on one side - A 4-ethoxyphenyl group on the other - The core is an α,β-unsaturated ketone (chalcone skeleton) ### Step 2: **General Chalcone Synthesis** Chalcones are typically synthesized by the **Claisen-Schmidt condensation**: - React an **aromatic aldehyde** with an **aromatic ketone** in basic conditions. ### Step 3: **Choose Appropriate Starting Materials** - **Aromatic aldehyde:** 4-bromo-benzaldehyde (Br–C₆H₄–CHO) - **Aromatic ketone:** 4-ethoxy-acetophenone (EtO–C₆H₄–COCH₃) ### Step 4: **Write the Reaction** \[ \text{4-bromobenzaldehyde} + \text{4-ethoxyacetophenone} \xrightarrow{\text{NaOH/EtOH}} \text{chalcone product} + H_2O \] **Expanded:** \[ \ce{ Br-C6H4-CHO + EtO-C6H4-COCH3 ->[\text{NaOH/EtOH}] Br-C6H4-CH=CH-CO-C6H4-OEt + H2O } \] --- ## 2. (B) IUPAC Name of the Chalcone ### Step 1: **Identify Parent Chain and Substituents** - **Parent chalcone:** 1,3-diphenylprop-2-en-1-one - **Substituents:** - 4-bromo on one phenyl ring - 4-ethoxy on the other phenyl ring ### Step 2: **Assign Numbers and Substituents** - The ketone is at position 1. - The double bond is at position 2. - Substituents are at para positions (4) on each ring. ### Step 3: **Name the Compound** **IUPAC Name:** **(E)-1-(4-bromophenyl)-3-(4-ethoxyphenyl)prop-2-en-1-one** --- ## **Final Answers** ### **2. (A) Chemical Equation** \[ \ce{ 4-bromobenzaldehyde + 4-ethoxyacetophenone ->[\text{NaOH/EtOH}] (E)-1-(4-bromophenyl)-3-(4-ethoxyphenyl)prop-2-en-1-one + H2O } \] ### **2. (B) IUPAC Name** **(E)-1-(4-bromophenyl)-3-(4-ethoxyphenyl)prop-2-en-1-one** --- Let me know if you need a step-by-step mechanism for the condensation!