Give step-by-step solution with explanation and final answer:A solid metal sphere of radius 8 cm, with a total charge of 10.13 mC, is surrounded by a metallic shell with a radius of 15 cm carrying a
-1.52 mC charge. The sphere and the shell are both inside a larger metallic shell of inner radius 20 cm and outer radius 24 cm. The
sphere and the two shells are concentric.
a. What is the charge on the inner wall of the larger shell? (Include a minus sign if necessary.)
—S
b. If the electric field outside the larger shell is zero, what is the charge on the outer wall of the shell?
[ue
Question:
Give step-by-step solution with explanation and final answer:A solid metal sphere of radius 8 cm, with a total charge of 10.13 mC, is surrounded by a metallic shell with a radius of 15 cm carrying a
-1.52 mC charge. The sphere and the shell are both inside a larger metallic shell of inner radius 20 cm and outer radius 24 cm. The
sphere and the two shells are concentric.
a. What is the charge on the inner wall of the larger shell? (Include a minus sign if necessary.)
—S
b. If the electric field outside the larger shell is zero, what is the charge on the outer wall of the shell?
[ue
This is AI generated Response.
Asked by: Om
Created at: 2026-02-02 05:23:49
Final Answer:
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Let's break down the problem step by step:
### **Given Data**
- Solid metal sphere (radius = 8 cm)
- Charge, \( Q_1 = 10.13 \) mC \( = 10,130 \) μC
- First metallic shell (radius = 15 cm)
- Charge, \( Q_2 = -1.52 \) mC \( = -1,520 \) μC
- Larger metallic shell (inner radius = 20 cm, outer = 24 cm)
- All shells and the sphere are **concentric**.
---
## **Step 1: Charge on the Inner Wall of the Larger Shell**
Let's call:
- **Sphere charge:** \( Q_1 = 10,130 \) μC
- **First shell total charge:** \( Q_2 = -1,520 \) μC
- **Larger shell:** Unknown charges on inner (\( Q_{a, \text{in}} \)) and outer (\( Q_{a, \text{out}} \)) walls
### **a. What is the charge on the inner wall of the larger shell?**
#### **Principle:**
The electric field inside a conductor in electrostatic equilibrium is zero.
**All charges inside the cavity up to the inner wall (20 cm) must be neutralized by the inner wall.**
#### **Total charge enclosed within 20 cm:**
- Sphere: \( Q_1 = 10,130 \) μC
- First shell: \( Q_2 = -1,520 \) μC
\[
Q_{\text{enclosed}} = Q_1 + Q_2 = 10,130 \, \mu\text{C} + (-1,520) \, \mu\text{C} = 8,610 \, \mu\text{C}
\]
#### **The inner wall must have a charge of:**
\[
Q_{a, \text{in}} = -Q_{\text{enclosed}} = -8,610 \, \mu\text{C}
\]
---
## **Step 2: Charge on the Outer Wall if the Field Outside is Zero**
### **b. If the electric field outside the larger shell is zero, what is the charge on the outer wall?**
If the field outside is zero, the **total charge** enclosed by the outer shell must be zero.
#### **Total charge inside (including both walls of shells and sphere):**
- Sphere: \( Q_1 = 10,130 \) μC
- First shell: \( Q_2 = -1,520 \) μC
- Inner wall of large shell: \( Q_{a, \text{in}} = -8,610 \) μC
- Outer wall of large shell: \( Q_{a, \text{out}} = ? \)
Set total charge to zero:
\[
Q_1 + Q_2 + Q_{a, \text{in}} + Q_{a, \text{out}} =
\]
\[
10,130 + (-1,520) + (-8,610) + Q_{a, \text{out}} =
\]
\[
10,130 - 1,520 - 8,610 + Q_{a, \text{out}} =
\]
\[
Q_{a, \text{out}} = 1,520 \, \mu\text{C}
\]
---
## **Final Answers**
### **a. Charge on the inner wall of the larger shell:**
\[
\boxed{-8,610 \, \mu\text{C}}
\]
### **b. Charge on the outer wall of the larger shell:**
\[
\boxed{1,520 \, \mu\text{C}}
\]
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