Give step-by-step solution with explanation and final answer:F; en
in, Cao Ca exit concentration of A (mol/L)
Chao inlet concentration of A (mol/L)
k 7 space time (s)
A B k first-order rate constant (s7*)
i Fout, Ca Xa conversion of A
Consider a liquid-phase, irreversible, first-order reaction A — B taking place in a Continuous Stirred
Tank Reactor (CSTR) operating at steady state and constant temperature. The reaction rate is given by
7A = —kCa.
(a) Sketch the exit concentration of reactant A, Cy, as a function of the space time, 7, by deriving the
design equation for the CSTR. On your plot, clearly indicate the inlet concentration Cao and the
asymptotic behavior of Cy as 7 approaches infinity.
(b) Plot the fractional conversion of reactant A, X, against the dimensionless Damkghler number, Da = kr,
by developing the relationship between conversion and the Damkéhler number from the CSTR design
equation. Illustrate how the conversion changes from a low value at low Da to a high value at high Da.
(c) Mlustrate the relationship between the reaction rate, —r4, and the exit concentration, Ca, by plotting
the rate law on a graph with Cy on the x-axis and —r4 on the y-axis. Explain how the rate constant, k,
corresponds to the slope of this linear plot.
Question:
Give step-by-step solution with explanation and final answer:F; en
in, Cao Ca exit concentration of A (mol/L)
Chao inlet concentration of A (mol/L)
k 7 space time (s)
A B k first-order rate constant (s7*)
i Fout, Ca Xa conversion of A
Consider a liquid-phase, irreversible, first-order reaction A — B taking place in a Continuous Stirred
Tank Reactor (CSTR) operating at steady state and constant temperature. The reaction rate is given by
7A = —kCa.
(a) Sketch the exit concentration of reactant A, Cy, as a function of the space time, 7, by deriving the
design equation for the CSTR. On your plot, clearly indicate the inlet concentration Cao and the
asymptotic behavior of Cy as 7 approaches infinity.
(b) Plot the fractional conversion of reactant A, X, against the dimensionless Damkghler number, Da = kr,
by developing the relationship between conversion and the Damkéhler number from the CSTR design
equation. Illustrate how the conversion changes from a low value at low Da to a high value at high Da.
(c) Mlustrate the relationship between the reaction rate, —r4, and the exit concentration, Ca, by plotting
the rate law on a graph with Cy on the x-axis and —r4 on the y-axis. Explain how the rate constant, k,
corresponds to the slope of this linear plot.
This is AI generated Response.
Asked by: Francis
Created at: 2026-01-29 08:38:26
Final Answer:
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Let's solve each part step-by-step.
---
# (a) **CSTR Design Equation and \( C_A \) vs. \( \tau \)**
### **Step 1: Write the CSTR Mole Balance**
At steady state:
\[
\text{In} - \text{Out} + \text{Generation} =
\]
For component \( A \):
\[
F_{in} C_{A} - F_{out} C_A + V(-kC_A) =
\]
With \( F_{in} = F_{out} = F \) and \( \tau = \frac{V}{F} \):
\[
F(C_{A} - C_A) - kVC_A =
\]
\[
C_{A} - C_A = k\tau C_A
\]
### **Step 2: Rearrange for \( C_A \) as a Function of \( \tau \)**
\[
C_{A} = C_A (1 + k\tau)
\]
\[
C_A = \frac{C_{A}}{1 + k\tau}
\]
### **Step 3: Sketch and Behavior**
- At \( \tau = \): \( C_A = C_{A} \)
- As \( \tau \to \infty \): \( C_A \to \) (asymptotic approach)
**Plot**: \( y \)-axis is \( C_A \), \( x \)-axis is \( \tau \). The curve starts at \( C_{A} \) and decreases asymptotically toward .
---
# (b) **Fractional Conversion \( X_A \) vs. Damköhler Number \( Da \)**
### **Step 1: Define Fractional Conversion**
\[
X_A = \frac{C_{A} - C_A}{C_{A}}
\]
### **Step 2: Substitute \( C_A \) from Part (a)**
\[
X_A = 1 - \frac{C_A}{C_{A}} = 1 - \frac{1}{1 + k\tau}
\]
### **Step 3: Define Damköhler Number**
\[
Da = k\tau
\]
So,
\[
X_A = 1 - \frac{1}{1 + Da}
\]
\[
X_A = \frac{Da}{1 + Da}
\]
### **Step 4: Plot Behavior**
- At \( Da \to \), \( X_A \to \)
- At \( Da \to \infty \), \( X_A \to 1 \)
**Plot**: \( y \)-axis is \( X_A \), \( x \)-axis is \( Da \). The curve starts at , approaches 1 asymptotically.
---
# (c) **Reaction Rate \( -r_A \) vs. Exit Concentration \( C_A \)**
### **Step 1: Write the Rate Law**
\[
-r_A = k C_A
\]
### **Step 2: Plot**
Plot \( -r_A \) (y-axis) vs. \( C_A \) (x-axis).
- This is a straight line through the origin with slope \( k \).
### **Step 3: Explanation**
- The slope of the line is the first-order rate constant \( k \).
- The larger \( k \), the steeper the line.
---
## **Summary of Answers**
### **(a)**
\[
\boxed{C_A = \frac{C_{A}}{1 + k\tau}}
\]
- Starts at \( C_{A} \), decreases to as \( \tau \to \infty \).
### **(b)**
\[
\boxed{X_A = \frac{Da}{1 + Da} = \frac{k\tau}{1 + k\tau}}
\]
- Starts at , increases to 1 as \( Da \to \infty \).
### **(c)**
- Plot \( -r_A \) vs. \( C_A \): straight line through origin, slope \( k \).
- The rate constant \( k \) is the slope of this line.
---
## **Sketches (Description)**
1. **\( C_A \) vs. \( \tau \):**
- Hyperbolic decay from \( C_{A} \) to .
2. **\( X_A \) vs. \( Da \):**
- Rises from to 1, approaching 1 asymptotically.
3. **\( -r_A \) vs. \( C_A \):**
- Straight line through origin, slope = \( k \).
If you need actual graphs or a more detailed algebraic derivation, let me know!
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