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Give step-by-step solution with explanation and final answer:Draw the product of the reaction shown below. Ignore inorganic byproducts. 8 I CuCl JoTTTTEEEEEER | E H 1 (") brag To Pan i Drawing H - ' ' RE ELE Atoms, Bonds on and Rings Ells Draw or tap a new bond to see « fi suggestions. Undo i © el e Done yV SN

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Give step-by-step solution with explanation and final answer:Uploaded ImageDraw the product of the reaction shown below. Ignore inorganic byproducts. 8 I CuCl JoTTTTEEEEEER | E H 1 (") brag To Pan i Drawing H - ' ' RE ELE Atoms, Bonds on and Rings Ells Draw or tap a new bond to see « fi suggestions. Undo i © el e Done yV SN

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Asked by: Rahul
Created at: 2026-01-26 04:03:49

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Let's break down the reaction step-by-step: ## Step 1: Identify the starting material - The starting material is **aniline** (C₆H₅NH₂). ## Step 2: Identify the reagents and their role - **I₂ (iodine)** - **CuCl₂ (copper(II) chloride)** - These reagents together are used for the **Sandmeyer reaction**, which converts an amine group (–NH₂) on a benzene ring to a halogen (in this case, iodine). ## Step 3: Reaction mechanism 1. **Diazotization**: The aniline is first converted to a diazonium salt (C₆H₅N₂⁺Cl⁻) using nitrous acid (not explicitly shown, but usually occurs in situ with CuCl₂ as a catalyst). 2. **Substitution**: The diazonium group (–N₂⁺) is replaced by an iodine atom (I) using I₂ and CuCl₂. ## Step 4: Draw the product - The product will be **iodobenzene** (C₆H₅I). ### Structure of the product: - A benzene ring with an iodine atom attached to one of the carbons (where the NH₂ group was originally attached). --- ## **Final Answer** ### The product is **iodobenzene**: ``` I | /-----\ | | | | \-----/ ``` Or in line structure: - A benzene ring with an Iodine (I) substituent. **Summary:** **Aniline** + I₂, CuCl₂ ⟶ **Iodobenzene** (C₆H₅I) (The NH₂ group is replaced by an I atom on the benzene ring.)

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