Let's break down the problem step-by-step: --- ## Step 1: **Identify the Type** - The substrate is a bromoalkane (specifically, 1-bromopentane). - The reagents are sodium acetate (CH₃CO₂Na) and DMSO (a polar aprotic solvent). With sodium acetate (a nucleophile) in DMSO (favors SN2 reactions), we expect a **nucleophilic substitution (SN2)** reaction. --- ## Step 2: **Predict the SN2 Reaction** - **SN2 reactions** occur with inversion of configuration and are favored by primary alkyl halides and polar aprotic solvents like DMSO. - The nucleophile (acetate, CH₃CO₂⁻) will attack the carbon attached to the bromine, displacing Br⁻. --- ## Step 3: **Write the Reaction** Starting compound: ``` CH₃-CH₂-CH₂-CH₂-CH₂Br (1-bromopentane) ``` Reaction with acetate: ``` CH₃-CH₂-CH₂-CH₂-CH₂Br + CH₃CO₂⁻ → CH₃-CH₂-CH₂-CH₂-CH₂O₂CCH₃ + Br⁻ ``` This is **pentyl acetate** (also called **amyl acetate**). --- ## Step 4: **Draw the Major Product** The major product is **pentyl acetate**: ``` CH₃CO₂CH₂CH₂CH₂CH₂CH₃ ``` Or as a structure: O || CH3—C—O—CH2—CH2—CH2—CH2—CH3 --- ## **Final Answer** **The major product is pentyl acetate (amyl acetate):**  *Image: Structure of pentyl acetate* (alt: pentyl acetate, with an ester bond between a pentyl group and an acetyl group) --- **Summary of Steps:** 1. Recognized the reaction as SN2 due to the substrate and solvent. 2. Understood that acetate replaces the bromine. 3. Drew the product: pentyl acetate.