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6 Which of the following alkenes

Question

Give step-by-step solution with explanation and final answer:3) Calculate th,
© the degree of unsaturation for the following molecule:
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) B)4 PE) i |
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VIPSolutions · Accepted Answer

Let's solve each question step by step:

---

## **Question 5: Calculate the degree of unsaturation**

**Structure:** Cyclohexane ring with an ethynyl group.

### **Degree of Unsaturation Formula**
$$
\text{Degree of Unsaturation} = \frac{2C + 2 - H}{2}
$$

**Count the atoms:**
- Carbons ($C$): 8 (6 in ring + 2 in ethynyl)
- Hydrogens ($H$): Draw the structure or count:  
  - Cyclohexane ring (6C, each with 2H except where the ethynyl group is attached, which loses 1H).
  - Ethynyl group ($\ce{C#CH}$): 1 H.

In total:  
  - Ring: 6C × 2H = 12H, but 1 position replaced by ethynyl, so 11H.
  - Ethynyl: 1H.
  - Total H = 11 + 1 = 12H.

But let's check with the structure:
- Cyclohexane: C6H12 (if fully saturated)
- Remove 1 H from one carbon for the ethynyl group: C6H11
- Ethynyl group: C2H

So total: C8H12.

Plug into the formula:
$$
\text{Degree of Unsaturation} = \frac{2(8) + 2 - 12}{2} = \frac{16 + 2 - 12}{2} = \frac{6}{2} = 3
$$

**Final Answer:**  
$$
\boxed{3}
$$

---

## **Question 6: Which of the following alkenes are terminal alkenes?**

**Terminal alkene:** Double bond at the end of the chain (one carbon of the double bond is at the end).

- **I**: Yes, terminal.
- **II**: Yes, terminal.
- **III**: No, internal.
- **IV**: No, internal.

**Final Answer:**  
$$
\boxed{\text{D) I and II}}
$$

---

## **Question 7: Predict the major product(s) of the following reaction.**

**Reaction:** Cyclohexene + HBr

**Mechanism:** 
- Alkene undergoes electrophilic addition.
- Markovnikov addition: Br adds to more substituted carbon.

**Look at the products:**
- **I:** Br at more substituted carbon (Markovnikov)
- **II:** Br at less substituted carbon (anti-Markovnikov)
- **III:** Same as II, just different drawing.
- **IV:** Br at more substituted carbon (same as I, different drawing).

So, **I and IV** are Markovnikov (major), **II and III** are anti-Markovnikov (minor).

**Final Answer:**  
$$
\boxed{\text{C) Only I and IV}}
$$

---

## **Question 8: Reagents necessary for the transformation.**

**Transformation:**  
- Cyclohexene with an ethyl group → trans-1,2-diol (syn addition of two OH groups).

**This is syn dihydroxylation.**

- **A:** Epoxidation (MCPBA) + acid workup: gives trans-diol (anti).
- **B:** OsO4, H2O2: syn addition of two OH groups.
- **C:** Hydration (not correct).

**Final Answer:**  
$$
\boxed{\text{B) OsO}_4, \text{H}_2\text{O}_2}
$$

---

## **Summary Table**

| Q# | Answer             |
|--- |---------------------|
| 5  | 3                   |
| 6  | D) I and II         |
| 7  | C) Only I and IV    |
| 8  | B) OsO4, H2O2       |

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