Give step-by-step solution with explanation and final answer:QUESTION 2 (29 MARKS) a. Propose syntheses to prepare each of the following compounds from the indicated starting material. fo} 0] i) Cros —_— ax ) ° IS) CH3 N i) ® R— Y © cl Cl iii) ® —_— > 5) Br
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Give step-by-step solution with explanation and final answer:
QUESTION 2 (29 MARKS)
a. Propose syntheses to prepare each of the following compounds from the
indicated starting material.
fo}
0]
i) Cros —_— ax )
° IS) CH3
N
i) ® R— Y ©
cl
Cl
iii) ® —_— > 5)
Br
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Asked by: Rahul
Created at: 2026-01-23 03:46:59
Asked by: Rahul
Created at: 2026-01-23 03:46:59
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Let's break down each synthesis step by step.
---
## **i) Synthesis from 4-methyl-1,3-dioxane-2,5-dione to 1-methyl-2,3-dihydro-1H-inden-1-one**
**Starting material:**
4-methyl-1,3-dioxane-2,5-dione (methylsuccinic anhydride)
**Product:**
1-methyl-2,3-dihydro-1H-inden-1-one
**Steps:**
1. **Friedel–Crafts Acylation**
- React methylsuccinic anhydride with benzene in the presence of AlCl₃.
- This acylates benzene to give 4-methyl-3-oxo-3,4-dihydro-2H-inden-1-one.
2. **Cyclization (Intramolecular Friedel–Crafts)**
- The acylated product will undergo cyclization under acidic conditions to give the indanone structure.
**Summary of steps:**
- Methylsuccinic anhydride + benzene, AlCl₃ → cyclize to 1-methyl-2,3-dihydro-1H-inden-1-one
---
## **ii) Synthesis from Benzene to 2-chloro-N-(4-methylphenyl)acetamide**
**Starting material:**
Benzene
**Product:**
2-chloro-N-(4-methylphenyl)acetamide
**Steps:**
1. **Nitration**
- Nitrate benzene (HNO₃/H₂SO₄) to get nitrobenzene.
2. **Reduction**
- Reduce nitrobenzene (Fe/HCl or catalytic hydrogenation) to aniline.
3. **Friedel–Crafts Alkylation**
- Alkylate aniline with methyl chloride (CH₃Cl), but since direct alkylation is difficult due to the amine group, **acetanilide protection** may be needed:
- Acetylate aniline (Ac₂O) → acetanilide
- Alkylate with CH₃Cl/AlCl₃ → p-methylacetanilide
- Hydrolyze to p-toluidine
4. **Acylation**
- React p-toluidine with chloroacetyl chloride (ClCH₂COCl) to get 2-chloro-N-(4-methylphenyl)acetamide.
**Summary of steps:**
- Benzene → nitrobenzene → aniline → p-toluidine → 2-chloro-N-(4-methylphenyl)acetamide
---
## **iii) Synthesis from Benzene to 1-bromo-4-chlorobenzene**
**Starting material:**
Benzene
**Product:**
1-bromo-4-chlorobenzene
**Steps:**
1. **Chlorination**
- Chlorinate benzene (Cl₂/FeCl₃) to get chlorobenzene.
2. **Bromination (Para-selective)**
- Brominate chlorobenzene (Br₂/FeBr₃). The chlorine directs the incoming bromine to the para position.
**Summary of steps:**
- Benzene → chlorobenzene → 1-bromo-4-chlorobenzene
---
## **Final Answers (Stepwise Summary)**
### **i)**
1. Friedel–Crafts acylation of methylsuccinic anhydride with benzene (AlCl₃)
2. Cyclization to form the indanone ring system
### **ii)**
1. Nitration of benzene
2. Reduction to aniline
3. Acetylation to acetanilide
4. Friedel–Crafts methylation (para-selective)
5. Hydrolysis to p-toluidine
6. Acylation with chloroacetyl chloride
### **iii)**
1. Chlorination of benzene
2. Bromination of chlorobenzene (para-selective)
---
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