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Give step-by-step solution with explanation and final answer:I 5. Foo tou react hm, rons sed civ ro mn be V2 rt So ose oS ea Sr Sv a yo re Imachaniam, or you can wee “8” and HA" or Dasa’ and “sce, eapaciely Z a 0 att SR C5. eR eee ed in oc bo, Une. ee po pc SA. eo oe dw. a. Ll ed

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Give step-by-step solution with explanation and final answer:Uploaded ImageI 5. Foo tou react hm, rons sed civ ro mn be V2 rt So ose oS ea Sr Sv a yo re Imachaniam, or you can wee “8” and HA" or Dasa’ and “sce, eapaciely Z a 0 att SR C5. eR eee ed in oc bo, Une. ee po pc SA. eo oe dw. a. Ll ed

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Asked by: Rahul
Created at: 2026-01-22 07:54:41

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Let's break down the reaction step-by-step and provide a detailed curved arrow mechanism. --- ## **Step-by-Step Solution** ### **Given Reaction** **Reactants:** - Benzyl alcohol derivative (Ph-CH₂OH) - ATP (Adenosine Triphosphate) - HS⁻ (Thiol) **Product:** - Benzyl thioester (Ph-CH₂-SR) --- ### **Step 1: Activation of Alcohol by ATP** ATP can act as a phosphorylating agent, converting the alcohol into a good leaving group (phosphate ester). #### **Mechanism:** 1. The lone pair of electrons on the alcohol oxygen attacks the γ-phosphorus atom of ATP (the terminal phosphate), displacing ADP and forming a **benzyl phosphate ester**. **Curved arrow:** - From alcohol O: lone pair → γ-phosphorus of ATP - From P-O bond in ATP: break bond, leaving as ADP **Intermediate formed:** Ph-CH₂-O-PO₃²⁻ (benzyl phosphate ester) --- ### **Step 2: Nucleophilic Substitution by Thiol** HS⁻ acts as a nucleophile, attacking the electrophilic carbon (benzylic carbon) and displacing the phosphate group via an **S_N2 mechanism**. #### **Mechanism:** 1. HS⁻ attacks the benzylic carbon from the backside, causing the O-PO₃²⁻ group to leave. **Curved arrow:** - From S⁻: lone pair → benzylic carbon - From C-O bond: break bond, electrons to O (leaving with phosphate) **Product formed:** Ph-CH₂-SH (benzyl thioether) --- ### **Final Answer: Detailed Mechanism** #### **Step 1: Formation of Benzyl Phosphate Ester** ```markdown O || Ph-CH2-OH + ATP → Ph-CH2-O-PO3^2- + ADP ``` - Alcohol attacks γ-phosphate of ATP; ADP leaves. #### **Step 2: Nucleophilic Substitution** ```markdown Ph-CH2-O-PO3^2- + HS^- → Ph-CH2-SH + PO4^3- ``` - Thiolate anion (HS⁻) attacks benzylic carbon, phosphate group leaves. --- ### **Curved Arrow Mechanism (Summary)** 1. **Nucleophilic attack by alcohol oxygen on ATP (γ-phosphate), forming benzyl phosphate ester.** 2. **Nucleophilic S_N2 attack by HS⁻ on benzylic carbon, displacing phosphate group and forming thioether.** --- ## **Final Product** The product is a **benzyl thioether**: **Ph-CH₂-SH** --- ### **Summary Table** | Step | Reactant(s) | Intermediate/Product | Key Transformation | |------|-----------------------|--------------------------|----------------------------------------| | 1 | Ph-CH₂OH + ATP | Ph-CH₂-O-PO₃²⁻ | Alcohol to phosphate ester (activation)| | 2 | Ph-CH₂-O-PO₃²⁻ + HS⁻ | Ph-CH₂-SH + PO₄³⁻ | S_N2 displacement by thiol | --- If you need a hand-drawn curved arrow mechanism, let me know!

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