Let's solve each reaction step-by-step. --- ## **1. Cyclohexene + H₂, Pd/C** ### **Step-by-Step Solution:** - **Reagent:** H₂ (hydrogen gas) with Pd/C (palladium on carbon) is a catalyst for **catalytic hydrogenation**. - **Reaction:** This reagent reduces (adds H₂ across) C=C double bonds, converting alkenes to alkanes. - **Starting Material:** Methylcyclohexene (a six-membered ring with one double bond and a methyl group). - **Product:** The double bond is reduced to a single bond, yielding **methylcyclohexane**. **Reaction:** \[ \text{Methylcyclohexene} \xrightarrow{\text{H}_2, \text{Pd/C}} \text{Methylcyclohexane} \] - **Reduction?** **Yes,** because hydrogen is being added to the molecule (increase in hydrogen, decrease in unsaturation). --- ## **2. 1-Butene + mCPBA** ### **Step-by-Step Solution:** - **Reagent:** mCPBA (meta-Chloroperoxybenzoic acid) is a **peracid**. - **Reaction:** mCPBA reacts with alkenes to form **epoxides** (epoxidation reaction). - **Starting Material:** 1-butene (CH₂=CH-CH₂-CH₃). - **Product:** The double bond forms a three-membered epoxide ring. Product is **1,2-epoxybutane** (butene oxide). **Reaction:** \[ \text{1-butene} \xrightarrow{\text{mCPBA}} \text{1,2-epoxybutane (butene oxide)} \] - **Reduction?** **No,** this is **not a reduction**. It's an oxidation, as an oxygen atom is inserted into the molecule. --- ## **Summary Table** | Reaction | Product | Reduction? | |----------|---------|------------| | Methylcyclohexene + H₂, Pd/C | Methylcyclohexane | Yes | | 1-Butene + mCPBA | 1,2-Epoxybutane (Butene oxide) | No | --- ### **Final Answers** 1. **Methylcyclohexene + H₂, Pd/C → Methylcyclohexane (This is a reduction)** 2. **1-Butene + mCPBA → 1,2-Epoxybutane (This is not a reduction, it is an oxidation)** Let me know if you need the structures drawn!