Give step-by-step solution with explanation and final answer:4 Propose a mechanism to account for the following addition reactions. Show the structure of the intermediates), and use curved arrows to follow electron flows in each step. (20P) . ee Fo a
Question:
Give step-by-step solution with explanation and final answer:
4 Propose a mechanism to account for the following
addition reactions. Show the structure of the
intermediates), and use curved arrows to follow electron
flows in each step. (20P)
.
ee
Fo
a
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Asked by: Rahul
Created at: 2026-01-18 16:54:02
Asked by: Rahul
Created at: 2026-01-18 16:54:02
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# Step-by Solution and Mechanism
The reaction shown is **addition of HBr to sty (phenylethene)**, you are asked to show the mechanism **in the absence and presence of peroxide (ROOR)**. The outcome depends on the conditions:
---
## 1. **Absence of Peroxide (Normal Addition, Markovnikov Rule)**
### **Stepwise Mechanism:**
#### **Step 1: Protonation of Alkene (Formation of Carbocation)**
- The alkene π electrons attack the proton (H⁺) from HBr.
- The most stable carbocation forms (Markovnikov rule: H adds to the carbon with more hydrogens).
**Curved arrows:**
- π electrons of the double bond attack the H of HBr.
- The Br– takes the electrons from the H–Br bond.
**Intermediate:**
- Benzyl carbocation (resonance-stabilized).
#### **Step 2: Nucleophilic Attack by Br⁻**
- The Br⁻ attacks the carbocation to give the Markovnikov product.
---
#### **Structures:**
**Step 1:**
```markdown
Ph-CH=CH2 + HBr → Ph-CH⁺-CH3 + Br⁻
| |
(styrene) (benzyl carbocation)
```
**Curved arrow:** from alkene to H, and from H–Br bond to Br.
**Step 2:**
```markdown
Ph-CH⁺-CH3 + Br⁻ → Ph-CH(Br)-CH3
```
**Product:** **1-bromo-1-phenylethane (Markovnikov product)**
---
## 2. **Presence of Peroxide (ROOR, Radical Addition, Anti-Markovnikov Rule)**
### **Stepwise Mechanism:**
#### **Step 1: Initiation (Radical Formation)**
- ROOR decomposes to form alkoxy radicals.
- Alkoxy radical abstracts H from HBr to generate Br• (bromine radical).
#### **Step 2: Propagation**
1. **Addition of Br• to Alkene**
- Br• adds to the less substituted carbon of the alkene (to form the more stable benzyl radical).
- **Anti-Markovnikov addition:** Br adds to the terminal carbon.
2. **Radical abstracts H from HBr**
- The new radical abstracts H from HBr, generating the product and another Br• radical (which continues the chain).
---
#### **Structures:**
**Initiation:**
```markdown
ROOR → 2 RO• (by heat/light)
RO• + HBr → ROH + Br•
```
**Propagation Step 1:**
Curved arrow: Br• attacks terminal carbon of double bond, forming benzyl radical.
```markdown
Ph-CH=CH2 + Br• → Ph-CH•-CH2Br
```
**Propagation Step 2:**
Curved arrow: Radical abstracts H from HBr.
```markdown
Ph-CH•-CH2Br + HBr → Ph-CH2-CH2Br + Br•
```
**Product:** **1-bromo-2-phenylethane (Anti-Markovnikov product)**
---
## **Summary Table**
| Condition | Product | Mechanism Type | Regioselectivity |
|---------------------|---------------------------------|---------------------|-------------------|
| No peroxide | 1-bromo-1-phenylethane | Ionic (carbocation) | Markovnikov |
| With peroxide (ROOR)| 1-bromo-2-phenylethane | Radical | Anti-Markovnikov |
---
## **Electron Flow (Curved Arrows):**
- **Ionic Addition:**
- Arrow from double bond to H of HBr.
- Arrow from H–Br bond to Br.
- Arrow from Br⁻ to carbocation.
- **Radical Addition:**
- Arrow from Br• to terminal carbon.
- Arrow from radical carbon to H of HBr.
- Arrow from H–Br bond to Br•.
---
## **Final Answers:**
### **Markovnikov Product (No Peroxide):**
- **Product:** 1-bromo-1-phenylethane
### **Anti-Markovnikov Product (With Peroxide):**
- **Product:** 1-bromo-2-phenylethane
---
Let me know if you need the **curved arrow diagrams** or any **structural drawings** for further clarification!
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