Give step-by-step solution with explanation and final answer: show the calculation for calculating saturation pressure of water at 256 deg C and calculation of specific volume at saturation pressure
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Give step-by-step solution with explanation and final answer: show the calculation for calculating saturation pressure of water at 256 deg C and calculation of specific volume at saturation pressure
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Asked by: Francis
Created at: 2026-01-09 16:09:31
Asked by: Francis
Created at: 2026-01-09 16:09:31
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# Step-by-Step Solution: Saturation Pressure and Specific Volume of Water at 256°C
We are tasked to find:
1. The **saturation pressure** of water at 256°C.
2. The **specific volume of saturated steam** at this pressure (i.e., at 256°C).
---
## 1. Finding Saturation Pressure at 256°C
The **saturation pressure** for a given temperature is the pressure at which water boils (liquid and vapor are in equilibrium) at that temperature. This value is typically found in **steam tables**.
### Using Steam Tables
Look up the row where the saturation temperature is **256°C**.
**From typical steam tables:**
| Temperature (°C) | Pressure (MPa) | Pressure (bar) |
|------------------|---------------|---------------|
| 255 | 3.983 | 39.83 |
| **256** | **4.056** | **40.56** |
| 257 | 4.130 | 41.30 |
**Saturation Pressure at 256°C:**
- \( P_{\text{sat, 256°C}} = 4.056 \) MPa
- Or \( 40.56 \) bar
---
## 2. Finding Specific Volume at Saturation Pressure
The **specific volume** at the saturation temperature and pressure can refer to either:
- \( v_f \): Specific volume of saturated liquid (water)
- \( v_g \): Specific volume of saturated vapor (steam)
Usually, for steam, the **specific volume of saturated vapor (\( v_g \))** is desired.
### From Steam Tables (at 256°C):
| Temperature (°C) | \( v_f \) (m³/kg) | \( v_g \) (m³/kg) |
|------------------|-------------------|-------------------|
| 255 | .001240 | .04837 |
| **256** | .001243 | .04797 |
| 257 | .001246 | .04757 |
- **Specific volume of saturated vapor at 256°C:**
\( v_g = .04797 \) m³/kg
- **Specific volume of saturated liquid at 256°C:**
\( v_f = .001243 \) m³/kg
---
## Final Answers
### 1. Saturation Pressure at 256°C
- \( P_{\text{sat}} = 4.056 \) MPa (or **40.56 bar**)
### 2. Specific Volume at Saturation Pressure (256°C)
- For vapor (steam):
\( v_g = .04797 \) m³/kg
- For liquid:
\( v_f = .001243 \) m³/kg
---
## Summary Table
| Value | At 256°C |
|----------------------|------------------|
| Saturation Pressure | 4.056 MPa (40.56 bar) |
| \( v_f \) (liquid) | .001243 m³/kg |
| \( v_g \) (vapor) | .04797 m³/kg |
---
**References:**
- [Steam Tables (IAPWS-IF97)](https://webbook.nist.gov/chemistry/fluid/)
- Standard Thermodynamics textbooks
---
**Note:**
Values may vary slightly depending on the steam table source, but these are typical. Always use the steam table provided for your course or industry for official calculations.
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