Give step-by-step solution with explanation and final answer: show the calculation for calculating saturation pressure of water at 2 5 6 deg C and calculation of specific volume at saturation pressure
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Give step-by-step solution with explanation and final answer: show the calculation for calculating saturation pressure of water at 2 5 6 deg C and calculation of specific volume at saturation pressure
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Asked by: Francis
Created at: 2026-01-09 15:27:38
Asked by: Francis
Created at: 2026-01-09 15:27:38
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# Saturation Pressure and Specific Volume of Water at Given Temperatures
Let's solve for the **saturation pressure** and **specific volume** of water at **2°C, 5°C, and 6°C**.
## Step 1: Understanding the Problem
- **Saturation pressure**: The pressure at which water boils (liquid and vapor coexist) at a given temperature.
- **Specific volume at saturation**: The volume occupied by unit mass of water vapor at saturation conditions.
We will use standard thermodynamic steam tables for the calculations.
---
## Step 2: Find Saturation Pressure (\(P_{sat}\))
Look up the saturation pressure corresponding to each temperature.
### **a) At 2°C**
From steam tables (values may slightly vary by source):
- **Saturation pressure (\(P_{sat}\)) at 2°C**:
\(P_{sat} \approx .00706\) bar
\(= .706\) kPa
### **b) At 5°C**
- **Saturation pressure (\(P_{sat}\)) at 5°C**:
\(P_{sat} \approx .00872\) bar
\(= .872\) kPa
### **c) At 6°C**
- **Saturation pressure (\(P_{sat}\)) at 6°C**:
\(P_{sat} \approx .00934\) bar
\(= .934\) kPa
---
## Step 3: Find Specific Volume of Saturated Vapor (\(v_g\)) at Each Temperature
Specific volume (\(v_g\)) is the volume per kg of water vapor at the saturation pressure.
### **a) At 2°C**
- **\(v_g\) at 2°C**:
\(v_g \approx 107.48\, \text{m}^3/\text{kg}\)
### **b) At 5°C**
- **\(v_g\) at 5°C**:
\(v_g \approx 98.63\, \text{m}^3/\text{kg}\)
### **c) At 6°C**
- **\(v_g\) at 6°C**:
\(v_g \approx 96.16\, \text{m}^3/\text{kg}\)
---
## Step 4: Summary Table
| Temperature (°C) | \(P_{sat}\) (bar) | \(P_{sat}\) (kPa) | \(v_g\) (\(\text{m}^3/\text{kg}\)) |
|------------------|-------------------|-------------------|----------------------|
| 2 | .00706 | .706 | 107.48 |
| 5 | .00872 | .872 | 98.63 |
| 6 | .00934 | .934 | 96.16 |
---
## Step 5: Final Answers
**At 2°C:**
- Saturation pressure: \(.00706\, \text{bar}\) (\(.706\, \text{kPa}\))
- Specific volume: \(107.48\, \text{m}^3/\text{kg}\)
**At 5°C:**
- Saturation pressure: \(.00872\, \text{bar}\) (\(.872\, \text{kPa}\))
- Specific volume: \(98.63\, \text{m}^3/\text{kg}\)
**At 6°C:**
- Saturation pressure: \(.00934\, \text{bar}\) (\(.934\, \text{kPa}\))
- Specific volume: \(96.16\, \text{m}^3/\text{kg}\)
---
## Step 6: Explanation
- **Steam tables** are used to determine the saturation pressure and specific volume at a given temperature.
- The specific volume of vapor decreases as temperature increases, because the density of vapor increases with temperature.
- The saturation pressure increases rapidly with temperature.
---
## References
- Thermodynamic Steam Tables (IAPWS, ASME)
- Yunus Çengel & Michael Boles, *Thermodynamics: An Engineering Approach*
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