VIPSolutionsGive step-by-step solution with explanation and final answer: A solution is prepared by dissolving 11.7 g of sodium chloride in water and making the final volume of the solution 1 liter. Calculate the molarity of the solution. (Molar mass of NaCI = 58.5 g/mol)
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Give step-by-step solution with explanation and final answer: A solution is prepared by dissolving 11.7 g of sodium chloride in water and making the final volume of the solution 1 liter. Calculate the molarity of the solution. (Molar mass of NaCI = 58.5 g/mol)
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Asked by: Rahul
Created at: 2026-01-01 09:25:52
Asked by: Rahul
Created at: 2026-01-01 09:25:52
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# Step-by-Step Solution
## Step 1: Write the Formula for Molarity
Molarity (\( M \)) is defined as:
\[
M = \frac{\text{moles of solute}}{\text{volume of solution in liters}}
\]
## Step 2: Calculate Moles of Sodium Chloride (NaCl)
Given:
- Mass of NaCl (\( m \)) = 11.7 g
- Molar mass of NaCl (\( M_m \)) = 58.5 g/mol
\[
\text{Moles of NaCl} = \frac{m}{M_m} = \frac{11.7\, \text{g}}{58.5\, \text{g/mol}} = .2\, \text{mol}
\]
## Step 3: Volume of Solution
- The final volume of solution (\( V \)) = 1 liter
## Step 4: Calculate the Molarity
\[
M = \frac{.2\, \text{mol}}{1\, \text{L}} = .2\, \text{mol/L}
\]
## Final Answer
**The molarity of the sodium chloride solution is:**
\[
\boxed{.2\, \text{M}}
\]
---
**Summary Table**
| Quantity | Value |
|----------------------|----------------|
| Mass of NaCl | 11.7 g |
| Molar mass of NaCl | 58.5 g/mol |
| Moles of NaCl | .2 mol |
| Volume of solution | 1. L |
| **Molarity** | **.2 M** |
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