# Step-by-Step Solution: Mass Flow Rate of Water Let's break down the problem step by step. ## Step 1: Understand What is Needed - We are asked to find the **mass flow rate** of water. - We know the **density of water** is \( 100 \) kg/m³. ## Step 2: Recall the Mass Flow Rate Formula The mass flow rate (\(\dot{m}\)) can be found using: \[ \dot{m} = \rho \cdot Q \] where: - \(\dot{m}\) = mass flow rate (kg/s) - \(\rho\) = density (kg/m³) - \(Q\) = volume flow rate (m³/s) ## Step 3: Identify What is Missing - The **volume flow rate** (\(Q\)) is needed. - The question refers to "the previous question." If you know the value of \(Q\), plug it in here. - If not given, let's just use the formula and show how you would use it. ## Step 4: Plug in the Values Suppose the volume flow rate is \(Q\) m³/s (replace with actual value if known). \[ \dot{m} = 100 \times Q \] So, the **mass flow rate** is \(100 \times Q\) kg/s. ## Step 5: Final Answer (With Explanation) **In simple words:** To find the mass flow rate, multiply the water's density (100 kg for every m³) by the number of m³ of water flowing each second (the volume flow rate). **Final formula:** \[ \text{Mass flow rate} = 100 \times \text{(volume flow rate)} \] - If you know the volume flow rate, just multiply it by 100 to get the answer in kg/s. --- **Example:** If \(Q = 2\) m³/s, \[ \text{Mass flow rate} = 100 \times 2 = 200 \text{ kg/s} \] ## Summary Table | Quantity | Symbol | Value | Units | |--------------------|--------|------------------|----------| | Density of water | \(\rho\) | 100 | kg/m³ | | Volume flow rate | \(Q\) | (given or known) | m³/s | | Mass flow rate | \(\dot{m}\) | \(100 \times Q\) | kg/s | --- **Remember:** - Use the actual volume flow rate from your question if you have it. - Always multiply by the density to get the mass flow rate.