VIPSolutionsGive step-by-step solution with explanation and final answer: Question:A chemical dryer removes moisture at the rate of 3.2kg per hour. If the dryer operates continuously for 19.5 hours, calculate the total moisture removed.
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Give step-by-step solution with explanation and final answer: Question:A chemical dryer removes moisture at the rate of 3.2kg per hour. If the dryer operates continuously for 19.5 hours, calculate the total moisture removed.
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Asked by: vemuri swathi
Created at: 2025-12-23 12:41:11
Asked by: vemuri swathi
Created at: 2025-12-23 12:41:11
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# Step-by-Step Solution
## Given Data
- **Moisture removal rate:** \(3.2\, \text{kg/hour}\)
**Operating time:** \(19.5\, \text{hours}\## Step 1: Write the Formula
To find the total moisture removed (\(M\)), use:
\[
M = \text{Rate} \times \text{Time}
\]
## Step 2: Substitute the Values
\[
M = 3.2\, \text{kg/hour} \times .5\, \text{hours}
\]
## Step 3: Perform the Multiplication
\[
3.2 \times 19.5 = 62.4
\]
## Step 4: Write the Final Answer
\[
\boxed{62.4\, \text{kg}}
\]
## Explanation
- The dryer removes 3.2 kg of moisture every hour.
- It runs for 19.5 hours, so multiply the rate by the time.
- The total moisture removed is **62.4 kg**.
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