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Give step-by-step solution with explanation and final answer:fae =~» Zo HE El FE 7 9 Baas B20 EEE E 3 3 ay 51 ie 2 us i v é E § | : : f i f 2 i g i 2

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Give step-by-step solution with explanation and final answer:Uploaded Imagefae =~» Zo HE El FE 7 9 Baas B20 EEE E 3 3 ay 51 ie 2 us i v é E § | : : f i f 2 i g i 2

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Asked by: Mallikarjun
Created at: 2025-12-16 03:33:00

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Let's break down and solve the given problem step by step. --- ## **Given Equation** \[ P = \left(\frac{N}{V}\right) k_B T - A \left(\frac{N}{V}\right)^{7/3} (k_B T)^{1/2} \] Where: - \(P\) = pressure - \(N\) = number of particles - \(V\) = volume - \(k_B\) = Boltzmann constant - \(T\) = temperature - \(A\) = a small constant --- ## **(a) Is this a valid equation of state?** **Equation of state:** A relation connecting state variables like \(P\), \(V\), \(T\), and \(N\). ### **Step 1: Form Check** - The equation relates \(P\), \(N\), \(V\), and \(T\). - The first term, \(\frac{N}{V} k_B T\), is the ideal gas law. - The second term introduces an interaction correction. ### **Step 2: Units Check** - \(\frac{N}{V}\) has units of \(\text{m}^{-3}\) (number density). - \(k_B T\) has units of energy (\(\text{J}\)). - \(P\) has units of \(\text{N/m}^2 = \text{J/m}^3\). #### **First term:** \[ \left(\frac{N}{V}\right) k_B T \Rightarrow \text{m}^{-3} \times \text{J} = \text{J/m}^3 \] Correct units for pressure. #### **Second term:** \[ A \left(\frac{N}{V}\right)^{7/3} (k_B T)^{1/2} \] Let’s check units: - \(\left(\frac{N}{V}\right)^{7/3}\): \(\text{m}^{-7}\) - \((k_B T)^{1/2}\): \(\text{J}^{1/2}\) - \(A\) must have units to make the total units \(\text{J/m}^3\). So, as long as \(A\) has appropriate units, the equation is dimensionally consistent. ### **Step 3: Physical Meaning** - The first term is the ideal gas contribution. - The second (negative) term is a correction, possibly from interactions. - For high \(T\) or low \(N/V\), the second term becomes negligible, reducing to the ideal gas law. ### **Conclusion** **Yes, this is a valid equation of state** for a gas with strong interactions, as it generalizes the ideal gas law with a correction term. --- ## **(b) Difference between \(C_P\) and \(C_V\) (using this equation of state):** ### **Step 1: Definitions** - \(C_V = \left(\frac{\partial Q}{\partial T}\right)_V = \left(\frac{\partial U}{\partial T}\right)_V\) - \(C_P = \left(\frac{\partial Q}{\partial T}\right)_P\) For any equation of state: \[ C_P - C_V = T \left(\frac{\partial P}{\partial T}\right)_V \left(\frac{\partial V}{\partial T}\right)_P \] For 1 mole (\(N\) fixed): \[ C_P - C_V = T \left(\frac{\partial P}{\partial T}\right)_V \left(\frac{\partial V}{\partial T}\right)_P \] ### **Step 2: Calculate \(\left(\frac{\partial P}{\partial T}\right)_V\)** Given: \[ P = n k_B T - A n^{7/3} (k_B T)^{1/2} \] Where \(n = \frac{N}{V}\) is constant at constant \(V\). \[ \left(\frac{\partial P}{\partial T}\right)_V = n k_B - A n^{7/3} \frac{1}{2} (k_B T)^{-1/2} k_B \] \[ = n k_B - \frac{A}{2} n^{7/3} k_B (k_B T)^{-1/2} \] ### **Step 3: Calculate \(\left(\frac{\partial V}{\partial T}\right)_P\)** At constant \(P\), implicitly differentiate the equation: \[ P = \frac{N}{V} k_B T - A \left(\frac{N}{V}\right)^{7/3} (k_B T)^{1/2} \] Let’s call \(x = \frac{N}{V}\): \[ P = x k_B T - A x^{7/3} (k_B T)^{1/2} \] Solve for \(V\) in terms of \(T\) at constant \(P\): - This is complex, but for small \(A\), treat second term as perturbation. For ideal gas (\(A=\)), \[ x = \frac{P}{k_B T} \rightarrow V = \frac{N k_B T}{P} \implies \left(\frac{\partial V}{\partial T}\right)_P = \frac{N k_B}{P} \] With small \(A\), the correction to \(\left(\frac{\partial V}{\partial T}\right)_P\) is small. ### **Step 4: Final Expression for Ideal Gas** For ideal gas (\(A = \)): \[ C_P - C_V = N k_B \] For this equation (to leading order in \(A\)), the difference is: \[ C_P - C_V = T \left[ n k_B - \frac{A}{2} n^{7/3} k_B (k_B T)^{-1/2} \right] \left( \frac{N k_B}{P} \right) \] Where \(P\) is given by the equation of state. --- ## **Summary / Final Answers** ### **(a)** **Yes, this is a valid equation of state.** It generalizes the ideal gas law by including a correction term for interactions, and is dimensionally consistent. ### **(b)** The difference between the heat capacity at constant pressure and at constant volume is: \[ C_P - C_V = T \left(\frac{\partial P}{\partial T}\right)_V \left(\frac{\partial V}{\partial T}\right)_P \] For this specific equation of state: \[ C_P - C_V = T \left[ n k_B - \frac{A}{2} n^{7/3} k_B (k_B T)^{-1/2} \right] \left( \frac{N k_B}{P} \right) \] where \(n = \frac{N}{V}\), and \(P\) is given by the equation of state. --- **Let me know if you need more detailed algebra for part (b)!**

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