Give step-by-step solution with explanation and final answer: 9. (5 points) Analytically determine the spectrum X(jw) of the continuous-time signal x(t) = 2 + 5cos(200pi*t - pi/6) Show and clearly label your work.
Question:
Give step-by-step solution with explanation and final answer: 9. (5 points) Analytically determine the spectrum X(jw) of the continuous-time signal x(t) = 2 + 5cos(200pi*t - pi/6) Show and clearly label your work.
This is AI generated Response.
Asked by: Aman
Created at: 2025-12-09 00:56:14
Asked by: Aman
Created at: 2025-12-09 00:56:14
Final Answer:
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# Step-by-Step Solution
Given signal:
\[
x(t) = 2 + 5\cos(200\pi t - \frac{\pi}{6})
\]
We are to find its spectrum \( X(j\omega) \), i.e., its **Fourier Transform**.
---
## 1. **Break Down the Signal**
The signal consists of:
- A DC component: \( 2 \)
- A cosine term: \( 5\cos(200\pi t - \frac{\pi}{6}) \)
---
## 2. **Fourier Transform of Each Component**
### **A. DC Term**
The Fourier Transform of a constant \( A \) is:
\[
\mathcal{F}\{A\} = 2\pi A \delta(\omega)
\]
So,
\[
\mathcal{F}\{2\} = 4\pi \delta(\omega)
\]
---
### **B. Cosine Term**
Recall:
\[
\cos(\omega_ t + \phi) = \frac{1}{2} \left[ e^{j(\omega_ t + \phi)} + e^{-j(\omega_ t + \phi)} \right]
\]
The Fourier Transform of \( \cos(\omega_ t + \phi) \) is:
\[
\pi \left[ e^{j\phi} \delta(\omega - \omega_) + e^{-j\phi} \delta(\omega + \omega_) \right]
\]
Here,
- Amplitude = 5
- \( \omega_ = 200\pi \)
- \( \phi = -\frac{\pi}{6} \)
So,
\[
\mathcal{F}\{5\cos(200\pi t - \frac{\pi}{6})\} = 5\pi \left[ e^{-j\frac{\pi}{6}} \delta(\omega - 200\pi) + e^{j\frac{\pi}{6}} \delta(\omega + 200\pi) \right]
\]
---
## 3. **Combine Results**
Add the two parts:
\[
X(j\omega) = 4\pi \delta(\omega) + 5\pi \left[ e^{-j\frac{\pi}{6}} \delta(\omega - 200\pi) + e^{j\frac{\pi}{6}} \delta(\omega + 200\pi) \right]
\]
---
## 4. **Final Answer (Labeled and Boxed)**
\[
\boxed{
X(j\omega) = 4\pi \delta(\omega) + 5\pi e^{-j\frac{\pi}{6}} \delta(\omega - 200\pi) + 5\pi e^{j\frac{\pi}{6}} \delta(\omega + 200\pi)
}
\]
---
## 5. **Interpretation**
- **At \( \omega = \):** DC component with magnitude \( 4\pi \)
- **At \( \omega = +200\pi \):** Spectral line with magnitude \( 5\pi \) and phase \( -\frac{\pi}{6} \)
- **At \( \omega = -200\pi \):** Spectral line with magnitude \( 5\pi \) and phase \( +\frac{\pi}{6} \)
---
**Summary Table:**
| Frequency (\(\omega\)) | Magnitude | Phase |
|-----------------------|-----------|------------------|
| | \(4\pi\) | |
| \(200\pi\) | \(5\pi\) | \(-\frac{\pi}{6}\) |
| \(-200\pi\) | \(5\pi\) | \(+\frac{\pi}{6}\) |
---
**No further computation is necessary. This is the complete analytical spectrum.**
Question:
Final answer not in table summary
This is AI generated Response.
Asked by: Aman
Created at: 2025-12-09 00:59:13
Asked by: Aman
Created at: 2025-12-09 00:59:13
Final Answer:
Rendered
Raw Text
Did you like this answer?
# Step-by-Step Solution
Given signal:
\[
x(t) = 2 + 5\cos(200\pi t - \frac{\pi}{6})
\]
We are to find its spectrum \( X(j\omega) \), i.e., its **Fourier Transform**.
---
## 1. **Break Down the Signal**
The signal consists of:
- A DC component: \( 2 \)
- A cosine term: \( 5\cos(200\pi t - \frac{\pi}{6}) \)
---
## 2. **Fourier Transform of Each Component**
### **A. DC Term**
The Fourier Transform of a constant \( A \) is:
\[
\mathcal{F}\{A\} = 2\pi A \delta(\omega)
\]
For our DC component:
\[
\mathcal{F}\{2\} = 4\pi \delta(\omega)
\]
### **B. Cosine Term**
Using the identity:
\[
\cos(\omega_0 t + \phi) = \frac{1}{2} \left[ e^{j(\omega_0 t + \phi)} + e^{-j(\omega_0 t + \phi)} \right]
\]
The Fourier Transform of \( \cos(\omega_0 t + \phi) \) is:
\[
\mathcal{F}\{\cos(\omega_0 t + \phi)\} = \pi \left[ e^{j\phi} \delta(\omega - \omega_0) + e^{-j\phi} \delta(\omega + \omega_0) \right]
\]
For our cosine component:
- Amplitude = 5
- \( \omega_0 = 200\pi \)
- \( \phi = -\frac{\pi}{6} \)
Thus,
\[
\mathcal{F}\{5\cos(200\pi t - \frac{\pi}{6})\} = 5\pi \left[ e^{-j\frac{\pi}{6}} \delta(\omega - 200\pi) + e^{j\frac{\pi}{6}} \delta(\omega + 200\pi) \right]
\]
---
## 3. **Combine Results**
Adding the two Fourier Transform results:
\[
X(j\omega) = 4\pi \delta(\omega) + 5\pi \left[ e^{-j\frac{\pi}{6}} \delta(\omega - 200\pi) + e^{j\frac{\pi}{6}} \delta(\omega + 200\pi) \right]
\]
---
## 4. **Final Answer**
The complete analytical spectrum is:
\[
\boxed{
X(j\omega) = 4\pi \delta(\omega) + 5\pi e^{-j\frac{\pi}{6}} \delta(\omega - 200\pi) + 5\pi e^{j\frac{\pi}{6}} \delta(\omega + 200\pi)
}
\]
---
## 5. **Interpretation**
- **At \( \omega = 0 \):** DC component with magnitude \( 4\pi \)
- **At \( \omega = +200\pi \):** Spectral line with magnitude \( 5\pi \) and phase \( -\frac{\pi}{6} \)
- **At \( \omega = -200\pi \):** Spectral line with magnitude \( 5\pi \) and phase \( +\frac{\pi}{6} \)
---
**Summary Table:**
| Frequency (\(\omega\)) | Magnitude | Phase |
|-----------------------|-----------|------------------|
| \(0\) | \(4\pi\) | \(0\) |
| \(200\pi\) | \(5\pi\) | \(-\frac{\pi}{6}\) |
| \(-200\pi\) | \(5\pi\) | \(+\frac{\pi}{6}\) |
---
This completes the analytical determination of the spectrum \( X(j\omega) \).
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