Give step-by-step solution with explanation and final answer: (give me answer withouy using bullet-points). a) Everything else being equal, write a general expression showing how the exchange current density varies as a function of reactant concentration.
Question:
Give step-by-step solution with explanation and final answer: (give me answer withouy using bullet-points). a) Everything else being equal, write a general expression showing how the exchange current density varies as a function of reactant concentration.
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Asked by: Francis
Created at: 2026-03-04 07:34:42
Asked by: Francis
Created at: 2026-03-04 07:34:42
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# Exchange Current Density and Reactant Concentration
The **exchange current density**( i_ \)) describes rate of electrochemical reaction at equilibrium (no net current), and is a central parameter in electrode kinetics.
The general expression for exchange current density is:
\[
i_ = n F k_ (C_{\text{Ox}}^{()})^{1-\alpha} (C_{\text{Red}}^{()})^{\alpha}
\]
Here, \( n \) is the number of electrons transferred, \( F \) is Faraday's constant, \( k_ \) is the standard rate constant, \( C_{\text{Ox}}^{()} \) and \( C_{\text{Red}}^{()} \) are the surface concentrations of the oxidized and reduced species respectively, and \( \alpha \) is the transfer coefficient (typically between and 1).
To focus on how \( i_ \) varies with reactant concentration (assuming \( k_ \), \( n \), \( F \), and \( \alpha \) are constant), we see that \( i_ \) is proportional to the oxidant concentration to the power of \( (1-\alpha) \) and the reductant concentration to the power of \( \alpha \):
\[
i_ \propto (C_{\text{Ox}})^{1-\alpha} (C_{\text{Red}})^{\alpha}
\]
**Final Answer:**
The exchange current density increases with increasing reactant concentrations, specifically as \( i_ \propto (C_{\text{Ox}})^{1-\alpha} (C_{\text{Red}})^{\alpha} \), where \( C_{\text{Ox}} \) and \( C_{\text{Red}} \) are the concentrations of oxidant and reductant, and \( \alpha \) is the transfer coefficient.
Question:
give me answer without empty brackets.
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Asked by: Francis
Created at: 2026-03-04 07:37:15
Asked by: Francis
Created at: 2026-03-04 07:37:15
Final Answer:
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# Exchange Current Density and Reactant Concentration
The **exchange current density** \( i \) describes the rate of an electrochemical reaction at equilibrium (no net current) and is a key parameter in electrode kinetics.
The general expression for exchange current density is given by:
\[
i = n F k (C_{\text{Ox}})^{1-\alpha} (C_{\text{Red}})^{\alpha}
\]
In this expression, \( n \) represents the number of electrons transferred, \( F \) is Faraday's constant, \( k \) denotes the standard rate constant, \( C_{\text{Ox}} \) and \( C_{\text{Red}} \) are the surface concentrations of the oxidized and reduced species respectively, and \( \alpha \) is the transfer coefficient, typically between 0 and 1.
To analyze how \( i \) varies with reactant concentration while keeping \( k \), \( n \), \( F \), and \( \alpha \) constant, we can simplify the expression. We find that \( i \) is proportional to the oxidant concentration raised to the power of \( (1-\alpha) \) and the reductant concentration raised to the power of \( \alpha \):
\[
i \propto (C_{\text{Ox}})^{1-\alpha} (C_{\text{Red}})^{\alpha}
\]
This indicates that the exchange current density increases with higher reactant concentrations.
**Final Answer:**
The exchange current density increases with increasing reactant concentrations, specifically as \( i \propto (C_{\text{Ox}})^{1-\alpha} (C_{\text{Red}})^{\alpha} \), where \( C_{\text{Ox}} \) and \( C_{\text{Red}} \) are the concentrations of oxidant and reductant, and \( \alpha \) is the transfer coefficient.
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