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Asked by: amu
Created at: 2025-07-25 08:15:19
Final Answer:
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Let's answer each question step by step, with explanations:
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### **Question 1**
#### π⁻ → μ⁻ + ν̅_μ: Dependence of decay rate on Cabibbo angle
- **Step 1:** The π⁻ (pion) is made of a \( \bar{u} \) and \( d \) quark. The decay process is:
\( d \rightarrow u + W^- \rightarrow u + \mu^- + \bar{\nu}_\mu \)
- **Step 2:** The transition \( d \rightarrow u \) is a weak interaction, and its strength is proportional to \( \cos \theta_c \) (Cabibbo angle).
- **Step 3:** The decay rate depends on the square of the amplitude, so it's proportional to \( \cos^2 \theta_c \).
**Final Answer:**
**c. cos² θ_c**
*The decay rate is proportional to \( \cos^2 \theta_c \) for this process.*
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### **Question 2**
#### Comparing decay probabilities:
τ⁻ → ν_τ + e⁻ + ν̅_e
τ⁻ → ν_τ + μ⁻ + ν̅_μ
- **Step 1:** Both decays are leptonic, and the weak interaction does not distinguish between electrons and muons (ignoring small phase space differences due to mass).
- **Step 2:** The only difference is the mass of the muon vs. electron, but the phase space suppression for the muon channel is small for the τ lepton.
**Final Answer:**
**The two decays have approximately equal probabilities**
*Both processes are mediated by the same weak interaction and are nearly equally probable.*
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### **Question 3**
#### Which quark is most likely to appear in s quark decays?
- **Step 1:** The s quark (strange) decays via the weak interaction, predominantly to a u quark (since s → u is CKM suppressed, but s → d is dominant).
- **Step 2:** In reality, the dominant decay is \( s \rightarrow u + W^- \), but since the answer choices are about which appears most likely, we look at which quark is produced directly via weak decay.
- **Step 3:** The s quark most commonly decays into a u quark (Cabibbo-favored).
**Final Answer:**
**u**
*The u quark is most likely to appear in s quark decays.*
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### **Question 4**
#### Which quark is most likely to be produced in c quark decays?
- **Step 1:** The c (charm) quark decays via the weak interaction, predominantly to a s quark.
- **Step 2:** This is due to the CKM matrix elements: \( c \rightarrow s \) is the most favored.
**Final Answer:**
**s**
*The s quark is most likely to be produced in c quark decays.*
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### **Question 5**
#### μ⁺ → e⁺ + ν̅_μ + ν_e: Dependence of decay rate on Cabibbo angle
- **Step 1:** This decay is purely leptonic, involving only leptons (no quarks).
- **Step 2:** The Cabibbo angle only affects weak decays involving quark flavor transitions, not purely leptonic decays.
**Final Answer:**
**No dependence**
*The decay rate does not depend on the Cabibbo angle for purely leptonic decays.*
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### **Question 6**
#### Lorentz structure of the weak charged interaction current
- **Step 1:** The weak charged current is described by the V–A (Vector minus Axial Vector) structure in the Standard Model.
- **Step 2:** This means the current is a combination: \( \text{Vector} - \text{Axial Vector} \).
**Final Answer:**
**Vector minus axial vector**
*The Lorentz structure is V–A (Vector minus Axial Vector).*
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## **Summary of Answers**
1. **c. cos² θ_c**
2. **The two decays have approximately equal probabilities**
3. **u**
4. **s**
5. **No dependence**
6. **Vector minus axial vector**
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