Let's break down the problem into **three steps** for each reaction. Here, I'll do the **first one** (with ethylenediamine, en), as an example: --- ### **1. Write the balanced reaction** **Given:** The reaction with ethylenediamine (en): \([Co(NH_3)_6]^{3+}\) **Reactants:** \([Co(NH_3)_6]^{3+} + 3\, en \rightarrow ?\) **Ethylenediamine (en)** is a bidentate ligand, so 3 en molecules can replace all 6 NH₃ ligands. **Balanced Reaction:** \[ [Co(NH_3)_6]^{3+} + 3\, en \rightarrow [Co(en)_3]^{3+} + 6\, NH_3 \] --- ### **2. Draw the structural formula (3D sketch)** - **[Co(en)₃]³⁺** is an **octahedral complex**. - Each **en** ligand forms two bonds (chelates) to the Co³⁺ center, so the structure has three rings. **Sketch:** ``` N / \ / \ N N \ / \ / Co / \ N N \ / N ``` (Imagine each en ligand wrapping around the Co³⁺ in a bidentate fashion, forming three chelate rings.) --- ### **3. Name the complex** - The complex is named **tris(ethylenediamine)cobalt(III) ion**. --- ## **Final Answer** 1. **Balanced Reaction:** \[ [Co(NH_3)_6]^{3+} + 3\, en \rightarrow [Co(en)_3]^{3+} + 6\, NH_3 \] 2. **Structural Formula:** Octahedral \([Co(en)_3]^{3+}\) (three bidentate ethylenediamine ligands chelating the Co³⁺) 3. **Name:** **tris(ethylenediamine)cobalt(III) ion** --- **If you want the other two reactions solved in this format, let me know!**