give answer in 3 steps with explanation at the end of each step and final answer at the end‘The binding of molecules in the gas phase 10 a sod surface s important in Catalysis and chromatography If we designate the.
ecules nh ga 85 A and he traced sufac a 5. the hs “dng” acusbrum fs A) 1S ++ SA whore SA
{woresents tac coogsed byte decd Amolecues For is bldg equllbu he acrpton equdon fs: ¥ = 125,
hic is cad he Langu squion. I he Langu austin, he volume of gas adsorbed ono th surface and Vs he
cme of gas adsrbed whch 08U 1 anclayer COV, 0 Complete Coverage of he sua by a ayer of olecules Acne
ecu hick Ao, P14 he prossurs areried by he 9a ri he fac a AAU and Py 4h eq Br presse
whan haf th surfaces covered. whch occurs when fp = 1 =
Panta
In std of gas ackcrpton cr sok sufacs, the volume of adsorbed ga Vs measured ssa uncton of he proses P.
Which oquaton 3 nearize om of he Langu ecuaton that woukd allow you 0 ban Vr, and Po fom the ope and
inercops?
ASwER
ako =v.y=}
Fe-kthie=vou=}
PVVaP RV 2=V.y=PV
$= iz=Py=§
Parts
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op. Fk ing a and tn. nt blr 1 cor ve Yo
pra
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Foe et at 20 , dein Py Gv yout rms tt.
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Question:
give answer in 3 steps with explanation at the end of each step and final answer at the end‘The binding of molecules in the gas phase 10 a sod surface s important in Catalysis and chromatography If we designate the.
ecules nh ga 85 A and he traced sufac a 5. the hs “dng” acusbrum fs A) 1S ++ SA whore SA
{woresents tac coogsed byte decd Amolecues For is bldg equllbu he acrpton equdon fs: ¥ = 125,
hic is cad he Langu squion. I he Langu austin, he volume of gas adsorbed ono th surface and Vs he
cme of gas adsrbed whch 08U 1 anclayer COV, 0 Complete Coverage of he sua by a ayer of olecules Acne
ecu hick Ao, P14 he prossurs areried by he 9a ri he fac a AAU and Py 4h eq Br presse
whan haf th surfaces covered. whch occurs when fp = 1 =
Panta
In std of gas ackcrpton cr sok sufacs, the volume of adsorbed ga Vs measured ssa uncton of he proses P.
Which oquaton 3 nearize om of he Langu ecuaton that woukd allow you 0 ban Vr, and Po fom the ope and
inercops?
ASwER
ako =v.y=}
Fe-kthie=vou=}
PVVaP RV 2=V.y=PV
$= iz=Py=§
Parts
Th olin oC a dtc re sched hr moc wa chard econ oO presse
donee
Pum 0m om om osm
Viet 0 oxo ove owe
sigur anes in tA, ma lt of he serpin sn. From ho bu gh in dekrin he
op. Fk ing a and tn. nt blr 1 cor ve Yo
pra
sree amt
nc
Fo ur to orn rn a Yrs
praen
— a
Po
Foe et at 20 , dein Py Gv yout rms tt.
prives
n
ane
Fo ye a lt comin Vi, Gre yout ner
ower
ar
pur
sing ur nor rs and . colon of gs ot wl bn rod cot rc hn
Ete
ve
This is AI generated Response.
Asked by: Anita
Created at: 2025-05-29 08:46:32
Final Answer:
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Let's solve this step by step, as requested. We'll break down the problem into three steps and explain each part:
---
### **Step 1: Identify the Correct Linearized Langmuir Equation (Part A)**
**Explanation:**
The Langmuir adsorption isotherm is:
\[
V = \frac{V_m P}{P_0 + P}
\]
To linearize, rearrange in a format \( y = mx + b \):
\[
\frac{P}{V} = \frac{P_0}{V_m} + \frac{P}{V_m}
\]
So, if you plot \(\frac{P}{V}\) (y-axis) vs \(P\) (x-axis), the slope is \(\frac{1}{V_m}\) and y-intercept is \(\frac{P_0}{V_m}\).
**Final answer for Step 1 (Part A):**
The correct linearized form is:
\[
\frac{P}{V} = \frac{P_0}{V_m} + \frac{P}{V_m}
\]
---
### **Step 2: Plot the Data and Find Slope and Intercept (Parts B & C)**
**Explanation:**
Now, using the data:
| P (atm) | V (mL) | P/V (atm/mL) |
|---------|--------|--------------|
| 0.132 | 0.128 | 1.031 |
| 0.264 | 0.150 | 1.760 |
| 0.396 | 0.160 | 2.475 |
| 0.528 | 0.166 | 3.181 |
Plot \(P/V\) (y-axis) vs \(P\) (x-axis). Fit a straight line: \(y = mx + b\).
You can use any graphing tool or calculate slope and intercept manually:
- Slope, \(m = \frac{\Delta y}{\Delta x}\)
- Intercept, \(b = y - mx\) (for any point)
Let's use the first and last points for a quick estimation:
\[
\text{Slope} = \frac{3.181 - 1.031}{0.528 - 0.132} = \frac{2.15}{0.396} \approx 5.43 \ \text{atm}^{-1}\text{mL}^{-1}
\]
\[
\text{Intercept} = 1.031 - (5.43 \times 0.132) = 1.031 - 0.717 = 0.314 \ \text{atm mL}^{-1}
\]
**Final answer for Step 2 (Parts B & C):**
- Slope: **5.43 atm\(^{-1}\) mL\(^{-1}\)**
- Y-intercept: **0.314 atm mL\(^{-1}\)**
---
### **Step 3: Calculate \(P_0\), \(V_m\), and Volume at \(P = 1\) atm (Parts D, E, F)**
**Explanation:**
From the linear form:
- Slope = \(1/V_m\) ⇒ \(V_m = 1/\text{slope}\)
- Intercept = \(P_0/V_m\) ⇒ \(P_0 = \text{intercept} \times V_m\)
Calculate \(V_m\):
\[
V_m = \frac{1}{5.43} = 0.184 \ \text{mL}
\]
Calculate \(P_0\):
\[
P_0 = 0.314 \times 0.184 = 0.0578 \ \text{atm}
\]
Now, calculate \(V\) at \(P = 1\) atm using the Langmuir equation:
\[
V = \frac{V_m P}{P_0 + P} = \frac{0.184 \times 1}{0.0578 + 1} = \frac{0.184}{1.0578} = 0.174 \ \text{mL}
\]
**Final answer for Step 3 (Parts D, E, F):**
- \(P_0 = 0.0578\) atm
- \(V_m = 0.184\) mL
- At \(P = 1\) atm, \(V = 0.174\) mL
---
## **Summary Table**
| Step | Value | Explanation |
|------|-------|-------------|
| 1 | \(\frac{P}{V} = \frac{P_0}{V_m} + \frac{P}{V_m}\) | Linearized Langmuir equation |
| 2 | Slope: 5.43 atm\(^{-1}\)mL\(^{-1}\)<br>Intercept: 0.314 atm mL\(^{-1}\) | From plot of \(P/V\) vs \(P\) |
| 3 | \(P_0 = 0.0578\) atm<br>\(V_m = 0.184\) mL<br>\(V_{P=1} = 0.174\) mL | Using results in Langmuir equation |
Let me know if you need the plot or more detailed calculations!
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