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give answer in 3 steps with explanation at the end of each step and final answer at the end‘The binding of molecules in the gas phase 10 a sod surface s important in Catalysis and chromatography If we designate the. ecules nh ga 85 A and he traced sufac a 5. the hs “dng” acusbrum fs A) 1S ++ SA whore SA {woresents tac coogsed byte decd Amolecues For is bldg equllbu he acrpton equdon fs: ¥ = 125, hic is cad he Langu squion. I he Langu austin, he volume of gas adsorbed ono th surface and Vs he cme of gas adsrbed whch 08U 1 anclayer COV, 0 Complete Coverage of he sua by a ayer of olecules Acne ecu hick Ao, P14 he prossurs areried by he 9a ri he fac a AAU and Py 4h eq Br presse whan haf th surfaces covered. whch occurs when fp = 1 = Panta In std of gas ackcrpton cr sok sufacs, the volume of adsorbed ga Vs measured ssa uncton of he proses P. Which oquaton 3 nearize om of he Langu ecuaton that woukd allow you 0 ban Vr, and Po fom the ope and inercops? ASwER ako =v.y=} Fe-kthie=vou=} PVVaP RV 2=V.y=PV $= iz=Py=§ Parts Th olin oC a dtc re sched hr moc wa chard econ oO presse donee Pum 0m om om osm Viet 0 oxo ove owe sigur anes in tA, ma lt of he serpin sn. From ho bu gh in dekrin he op. Fk ing a and tn. nt blr 1 cor ve Yo pra sree amt nc Fo ur to orn rn a Yrs praen — a Po Foe et at 20 , dein Py Gv yout rms tt. prives n ane Fo ye a lt comin Vi, Gre yout ner ower ar pur sing ur nor rs and . colon of gs ot wl bn rod cot rc hn Ete ve

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give answer in 3 steps with explanation at the end of each step and final answer at the endUploaded Image‘The binding of molecules in the gas phase 10 a sod surface s important in Catalysis and chromatography If we designate the. ecules nh ga 85 A and he traced sufac a 5. the hs “dng” acusbrum fs A) 1S ++ SA whore SA {woresents tac coogsed byte decd Amolecues For is bldg equllbu he acrpton equdon fs: ¥ = 125, hic is cad he Langu squion. I he Langu austin, he volume of gas adsorbed ono th surface and Vs he cme of gas adsrbed whch 08U 1 anclayer COV, 0 Complete Coverage of he sua by a ayer of olecules Acne ecu hick Ao, P14 he prossurs areried by he 9a ri he fac a AAU and Py 4h eq Br presse whan haf th surfaces covered. whch occurs when fp = 1 = Panta In std of gas ackcrpton cr sok sufacs, the volume of adsorbed ga Vs measured ssa uncton of he proses P. Which oquaton 3 nearize om of he Langu ecuaton that woukd allow you 0 ban Vr, and Po fom the ope and inercops? ASwER ako =v.y=} Fe-kthie=vou=} PVVaP RV 2=V.y=PV $= iz=Py=§ Parts Th olin oC a dtc re sched hr moc wa chard econ oO presse donee Pum 0m om om osm Viet 0 oxo ove owe sigur anes in tA, ma lt of he serpin sn. From ho bu gh in dekrin he op. Fk ing a and tn. nt blr 1 cor ve Yo pra sree amt nc Fo ur to orn rn a Yrs praen — a Po Foe et at 20 , dein Py Gv yout rms tt. prives n ane Fo ye a lt comin Vi, Gre yout ner ower ar pur sing ur nor rs and . colon of gs ot wl bn rod cot rc hn Ete ve

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Asked by: Anita
Created at: 2025-05-29 08:46:32

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Let's solve this step by step, as requested. We'll break down the problem into three steps and explain each part: --- ### **Step 1: Identify the Correct Linearized Langmuir Equation (Part A)** **Explanation:** The Langmuir adsorption isotherm is: \[ V = \frac{V_m P}{P_0 + P} \] To linearize, rearrange in a format \( y = mx + b \): \[ \frac{P}{V} = \frac{P_0}{V_m} + \frac{P}{V_m} \] So, if you plot \(\frac{P}{V}\) (y-axis) vs \(P\) (x-axis), the slope is \(\frac{1}{V_m}\) and y-intercept is \(\frac{P_0}{V_m}\). **Final answer for Step 1 (Part A):** The correct linearized form is: \[ \frac{P}{V} = \frac{P_0}{V_m} + \frac{P}{V_m} \] --- ### **Step 2: Plot the Data and Find Slope and Intercept (Parts B & C)** **Explanation:** Now, using the data: | P (atm) | V (mL) | P/V (atm/mL) | |---------|--------|--------------| | 0.132 | 0.128 | 1.031 | | 0.264 | 0.150 | 1.760 | | 0.396 | 0.160 | 2.475 | | 0.528 | 0.166 | 3.181 | Plot \(P/V\) (y-axis) vs \(P\) (x-axis). Fit a straight line: \(y = mx + b\). You can use any graphing tool or calculate slope and intercept manually: - Slope, \(m = \frac{\Delta y}{\Delta x}\) - Intercept, \(b = y - mx\) (for any point) Let's use the first and last points for a quick estimation: \[ \text{Slope} = \frac{3.181 - 1.031}{0.528 - 0.132} = \frac{2.15}{0.396} \approx 5.43 \ \text{atm}^{-1}\text{mL}^{-1} \] \[ \text{Intercept} = 1.031 - (5.43 \times 0.132) = 1.031 - 0.717 = 0.314 \ \text{atm mL}^{-1} \] **Final answer for Step 2 (Parts B & C):** - Slope: **5.43 atm\(^{-1}\) mL\(^{-1}\)** - Y-intercept: **0.314 atm mL\(^{-1}\)** --- ### **Step 3: Calculate \(P_0\), \(V_m\), and Volume at \(P = 1\) atm (Parts D, E, F)** **Explanation:** From the linear form: - Slope = \(1/V_m\) ⇒ \(V_m = 1/\text{slope}\) - Intercept = \(P_0/V_m\) ⇒ \(P_0 = \text{intercept} \times V_m\) Calculate \(V_m\): \[ V_m = \frac{1}{5.43} = 0.184 \ \text{mL} \] Calculate \(P_0\): \[ P_0 = 0.314 \times 0.184 = 0.0578 \ \text{atm} \] Now, calculate \(V\) at \(P = 1\) atm using the Langmuir equation: \[ V = \frac{V_m P}{P_0 + P} = \frac{0.184 \times 1}{0.0578 + 1} = \frac{0.184}{1.0578} = 0.174 \ \text{mL} \] **Final answer for Step 3 (Parts D, E, F):** - \(P_0 = 0.0578\) atm - \(V_m = 0.184\) mL - At \(P = 1\) atm, \(V = 0.174\) mL --- ## **Summary Table** | Step | Value | Explanation | |------|-------|-------------| | 1 | \(\frac{P}{V} = \frac{P_0}{V_m} + \frac{P}{V_m}\) | Linearized Langmuir equation | | 2 | Slope: 5.43 atm\(^{-1}\)mL\(^{-1}\)<br>Intercept: 0.314 atm mL\(^{-1}\) | From plot of \(P/V\) vs \(P\) | | 3 | \(P_0 = 0.0578\) atm<br>\(V_m = 0.184\) mL<br>\(V_{P=1} = 0.174\) mL | Using results in Langmuir equation | Let me know if you need the plot or more detailed calculations!

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