give answer in 2 steps with explanation at the end of each step and final answer at the end :go) =e] W THE BE Eee tery 8 a. Calculate tatistic to iny variabl it the -, \ i
Question:
give answer in 2 steps with explanation at the end of each step and final answer at the end :
go) =e]
W THE
BE Eee
tery
8
a. Calculate tatistic to iny
variabl it the -, \ i
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Asked by: Test User 100183
Created at: 2025-05-07 21:37:23
Asked by: Test User 100183
Created at: 2025-05-07 21:37:23
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Let's break down the solution into **two clear steps** with explanations after each step, and then provide the final answer.
---
### **Step 1: Calculate the Pearson Correlation Coefficient (r)**
#### **Data Table**
| Social Engagement (X) | Flourishing (Y) |
|-----------------------|-----------------|
| 9 | 6 |
| 4 | 4 |
| 8 | 5 |
| 7 | 3 |
| 5 | 6 |
| 4 | 3 |
| 9 | 7 |
| 6 | 5 |
| 10 | 9 |
| 13 | 9 |
| 7 | 6 |
| 8 | 7 |
Let’s calculate the necessary sums for the Pearson r formula:
\[
r = \frac{n(\sum XY) - (\sum X)(\sum Y)}{\sqrt{[n\sum X^2 - (\sum X)^2][n\sum Y^2 - (\sum Y)^2]}}
\]
#### **Calculate sums:**
- \( n = 12 \)
- \( \sum X = 90 \)
- \( \sum Y = 70 \)
- \( \sum X^2 = 748 \)
- \( \sum Y^2 = 454 \)
- \( \sum XY = 572 \)
---
#### **Substitute into the formula:**
\[
r = \frac{12(572) - (90)(70)}{\sqrt{[12 \times 748 - (90)^2][12 \times 454 - (70)^2]}}
\]
\[
r = \frac{6864 - 6300}{\sqrt{[8976 - 8100][5448 - 4900]}}
\]
\[
r = \frac{564}{\sqrt{876 \times 548}}
\]
\[
r = \frac{564}{\sqrt{479,448}}
\]
\[
r = \frac{564}{692.41}
\]
\[
r \approx 0.81
\]
**Explanation:**
The Pearson correlation coefficient \( r \approx 0.81 \) suggests a strong positive relationship between social engagement and flourishing.
---
### **Step 2: Test the significance of the correlation coefficient**
The test statistic for significance:
\[
t = \frac{r\sqrt{n-2}}{\sqrt{1 - r^2}}
\]
\[
t = \frac{0.81\sqrt{12-2}}{\sqrt{1 - (0.81)^2}}
\]
\[
t = \frac{0.81 \times 3.16}{\sqrt{1 - 0.6561}}
\]
\[
t = \frac{2.56}{\sqrt{0.3439}}
\]
\[
t = \frac{2.56}{0.586}
\]
\[
t \approx 4.37
\]
Degrees of freedom \( df = n-2 = 10 \).
At \( \alpha = 0.05 \) (two-tailed), critical t-value for df = 10 is approximately ±2.228.
- \( |t| = 4.37 > 2.228 \)
**Explanation:**
Since our calculated t-value is greater than the critical value, we reject the null hypothesis. The correlation is **statistically significant** at the .05 level.
---
## **Final Answer:**
### **a. Calculation and Hypothesis Testing Steps:**
1. The Pearson correlation coefficient is **r ≈ 0.81**, indicating a strong positive relationship.
2. The t-test result (**t ≈ 4.37**, df = 10, p < .05) shows this correlation is statistically significant.
### **b. Interpretation:**
- **Direction:** Positive (as social engagement increases, flourishing increases)
- **Magnitude/Size:** Strong (r ≈ 0.81)
- **Coefficient of determination:** \( r^2 = (0.81)^2 ≈ 0.66 \)
This means about **66% of the variance** in flourishing can be explained by social engagement.
---
**Summary:**
There is a strong, positive, and statistically significant relationship between social engagement and flourishing among these students, with social engagement explaining about 66% of the variance in flourishing.
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