## Step 1: Understanding the Problem and Extracting Data From the image: - Two masses are connected by light rods and rotating about the top point. - The lower mass is at the end of the rods. - The distance from the rotation point to the lower mass is \(4\,\text{m}\- The tension the rod is as \(T = 15.\,\textN}\). Explanation:** The speed of the lower mass can be found using the centripetal force formula: \[ T = m v^2 / r \] where: - \(T\) = tension (centripetal force) = \(15.5\,\text{N}\) - \(r\) = radius = \(4\,\text{m}\) - \(v\) = speed of the lower mass - \(m\) = mass of the lower object (not given, but not needed since only tension and radius are provided) ## Step 2: Solving for Speed Rearrange the centripetal force formula to solve for \(v\): \[ T = m \frac{v^2}{r} \] But since \(m\) is not given, check if the answer can be deduced from the values that are provided. Using the options, let's check for the value that, when plugged into the formula, gives the closest value to the given tension (assuming \(m\) is 1 kg for a ratio check): Try \(v = 8\,\text{m/s}\) (option c): \[ T = m \frac{v^2}{r} = m \frac{8^2}{4} = m \frac{64}{4} = 16m \] If \(m = 1\) kg, \(T = 16\,\text{N}\), which is closest to the given tension \(15.5\,\text{N}\). **Explanation:** Given the information and provided answer choices, \(8\,\text{m/s}\) gives a tension value closest to the provided \(15.5\,\text{N}\) when the mass is about 1 kg. --- ## **Final Answer** The speed of the lower mass is closest to: **c. 8 m/s**