## Step 1: Identify Series and Parallel Groups Let's analyze the circuit: - All capacitors have the same value \( C = 16 \mu F \). - There are three horizontal branches, each with two capacitors in **series**. For two capacitors in series: \[ C_{series} = \frac{C}{2} = \frac{16}{2} = 8 \mu F \] **Explanation:** Each horizontal branch reduces to a single 8 μF capacitor. --- ## Step 2: Combine the Parallel Capacitors Now, these three resulting 8 μF capacitors are in **parallel**: \[ C_{eq} = 8 + 8 + 8 = 24 \mu F \] **Explanation:** Capacitors in parallel add directly. --- ## Final Answer \[ \boxed{24 \ \mu F} \]