The image shows a partial question: "**...mine the time it...; and L = 60 mH**" It seems to involve an RL circuit (since L is inductance) and asks for time, likely involving the time constant. Let's solve assuming the question is: "Determine the time it takes for the current in an RL circuit to reach some value, given R = 25 Ω and L = 60 mH." ### Step 1: Find the Time Constant (τ) The time constant for an RL circuit is: \[ \tau = \frac{L}{R} \] Given: - \( L = 60 \) mH \( = .060 \) H - \( R = 25 \) Ω \[ \tau = \frac{.060}{25} = .0024 \text{ s} \] **Explanation:** The time constant tells you how quickly the current increases or decreases in the RL circuit. --- ### Step 2: Express the Current Growth The current in an RL circuit when a voltage is applied grows as: \[ I(t) = I_{max}(1 - e^{-t/\tau}) \] If the question asks for the time to reach a certain percentage of the final value (often 63.2%), that's at \( t = \tau \). If not specified, we can state the general relationship. For example, to reach 63.2% of the final current: \[ t = \tau = .0024 \text{ s} \] **Explanation:** After one time constant (\( \tau \)), the current reaches about 63.2% of its maximum value in an RL circuit. --- ## Final Answer **The time constant for the circuit is \( .0024 \) seconds (2.4 ms). After this time, the current reaches 63.2% of its final value.** If you specify another percentage or final current, let me know!