give answer in 2 step with explanation at the end of each step and final answer at the end:PA Incoch cae, determine he reslant moment of he oes acing shot 3. 1 2 0 [oN ’ od A Ey J ax on 5 Pe wy A Ton ® a - HON a — 5 = < < Si fox © Fons
Question:
give answer in 2 step with explanation at the end of each step and final answer at the end:
PA Incoch cae, determine he reslant moment of he
oes acing shot 3. 1 2 0
[oN
’
od
A Ey
J
ax
on 5
Pe
wy
A Ton
®
a
- HON
a
— 5
= <
<
Si fox
©
Fons
This is AI generated Response.
Asked by: Rahul
Created at: 2025-11-19 06:09:01
Asked by: Rahul
Created at: 2025-11-19 06:09:01
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Let's solve **Problem P3-3(a)** step by step as requested:
---
## **Step 1: Write Position Vectors and Force Vectors**
Choose the origin (O) at the bottom left corner of the plate.
**Coordinates of force application points:**
- **200 N (upwards, at A):** (, , )
- **50 N (upwards, at B):** (, 3, )
- **100 N (upwards, at C):** (2, 3, )
- **300 N (upwards, at D):** (2, , )
**Force vectors:**
All forces act in the **positive z-direction**:
- \(\vec{F}_1 = 200\hat{k}\) at (,,)
- \(\vec{F}_2 = 50\hat{k}\) at (,3,)
- \(\vec{F}_3 = 100\hat{k}\) at (2,3,)
- \(\vec{F}_4 = 300\hat{k}\) at (2,,)
---
**Explanation:**
We identified the coordinates where each force is applied and wrote their vectors.
---
## **Step 2: Calculate the Moment of Each Force About the Origin**
The moment of a force about the origin is:
\[
\vec{M} = \vec{r} \times \vec{F}
\]
Calculate for each force:
### **Force at A (origin):**
\[
\vec{r}_1 = (, , ), \ \vec{F}_1 = (, , 200)
\]
\[
\vec{M}_1 = \vec{r}_1 \times \vec{F}_1 = (,,)
\]
### **Force at B:**
\[
\vec{r}_2 = (, 3, ), \ \vec{F}_2 = (, , 50)
\]
\[
\vec{M}_2 =
\begin{vmatrix}
\hat{i} & \hat{j} & \hat{k} \\
& 3 & \\
& & 50
\end{vmatrix}
= (3 \cdot 50)\hat{i} - ( \cdot 50)\hat{j} + ()\hat{k} = 150\hat{i}
\]
### **Force at C:**
\[
\vec{r}_3 = (2, 3, ), \ \vec{F}_3 = (, , 100)
\]
\[
\vec{M}_3 =
\begin{vmatrix}
\hat{i} & \hat{j} & \hat{k} \\
2 & 3 & \\
& & 100
\end{vmatrix}
= (3 \cdot 100)\hat{i} - (2 \cdot 100)\hat{j} = 300\hat{i} - 200\hat{j}
\]
### **Force at D:**
\[
\vec{r}_4 = (2, , ), \ \vec{F}_4 = (, , 300)
\]
\[
\vec{M}_4 =
\begin{vmatrix}
\hat{i} & \hat{j} & \hat{k} \\
2 & & \\
& & 300
\end{vmatrix}
= ( - )\hat{i} - (2 \cdot 300)\hat{j} + ()\hat{k} = -600\hat{j}
\]
---
**Explanation:**
We calculated the moment for each force using the cross product formula.
---
## **Step 3: Sum the Moments to Get the Resultant**
Sum the \( \hat{i} \) and \( \hat{j} \) components:
\[
\vec{M}_{\text{res}} = ( + 150 + 300 + )\hat{i} + ( + - 200 - 600)\hat{j} + \hat{k}
\]
\[
\vec{M}_{\text{res}} = 450\hat{i} - 800\hat{j} \ \text{N}\cdot\text{m}
\]
---
### **Final Answer:**
\[
\boxed{
\vec{M}_{\text{res}} = 450\hat{i} - 800\hat{j} \ \text{N}\cdot\text{m}
}
\]
- Moment about x-axis (\(M_x\)): \(450\) N·m
- Moment about y-axis (\(M_y\)): \(-800\) N·m
- Moment about z-axis (\(M_z\)): \(\) N·m
---
If you want solutions for (b) or (c), let me know!
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