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Asked by: Rahul
Created at: 2025-11-15 15:47:21
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Let's solve each part step by step, with explanations after each step, and the final answers at the end.
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## **9.18 Provide systematic names for the compounds**
### **a. Structure: N(CH₂CH₃)₂ attached to a butane backbone**
#### **Step 1:** Identify the backbone and substituents.
- The backbone is butane (4 carbons).
- There is a diethylamino group (N(CH₂CH₃)₂) on the second carbon.
#### **Explanation:**
The parent chain is butane, and the diethylamino group is attached to carbon 2.
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### **b. Structure: Cyclohexane ring with a methyl and N-methylamino substituent**
#### **Step 2:** Assign locants and names.
- Cyclohexane ring is the parent.
- Methyl group at carbon 1, N-methylamino group at carbon 2.
#### **Explanation:**
Start numbering at the methyl group, so the substituents are at carbons 1 and 2.
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### **Final Answers for 9.18:**
- **a.** 2-(Diethylamino)butane
- **b.** 1-Methyl-2-(N-methylamino)cyclohexane
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## **9.36 Predict the products of the following S_N1 reactions**
### **a. 3-Chloro-3-methylpentane + (CH₃)₂NH**
#### **Step 1:** Carbocation formation
- The leaving group (Cl⁻) leaves, forming a tertiary carbocation at C-3.
#### **Step 2:** Nucleophilic attack
- Dimethylamine ((CH₃)₂NH) attacks the carbocation, forming an amine product.
#### **Explanation:**
S_N1 proceeds via a carbocation intermediate, then nucleophile attacks.
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### **b. 1-Bromo-1-phenylpropane + ethanol**
#### **Step 1:** Carbocation formation
- The leaving group (Br⁻) leaves, forming a benzylic carbocation (stabilized by the phenyl ring).
#### **Step 2:** Nucleophilic attack
- Ethanol attacks the carbocation, forming an ether after deprotonation.
#### **Explanation:**
Benzylic carbocation is stabilized, so S_N1 proceeds easily.
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### **Final Answers for 9.36:**
- **a.** 3-(Dimethylamino)-3-methylpentane
- **b.** 1-Ethoxy-1-phenylpropane
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## **9.44 Predict the mechanism for each reaction and draw the product(s)**
Let's address a few examples:
### **a. 1-Butyl tosylate + KCN**
#### **Step 1:** Mechanism
- KCN is a strong nucleophile. S_N2 reaction.
#### **Step 2:** Product
- Nucleophile (CN⁻) replaces OTs, forming 1-cyanobutane.
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### **b. 1-Butyl tosylate + NH₃**
#### **Step 1:** Mechanism
- NH₃ is a nucleophile. S_N2 reaction.
#### **Step 2:** Product
- Nucleophile (NH₃) replaces OTs, forming 1-butylamine.
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### **Final Answers for 9.44 (a & b):**
- **a.** S_N2; **Product:** 1-cyanobutane (butanenitrile)
- **b.** S_N2; **Product:** 1-butylamine
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**If you want detailed mechanisms or the rest of 9.44, let me know!**
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