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give answer in 2 step with explanation at the end of each step and final answer at the solved all parts end:a Draw the product of this reaction. Ignore inorganic byproducts. 1.mCPBA 2.Hs0* PEE CCE IS i ' | | ' ' A Select to Draw \ 1 | ' ' ' '

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give answer in 2 step with explanation at the end of each step and final answer at the solved all parts end:Uploaded Imagea Draw the product of this reaction. Ignore inorganic byproducts. 1.mCPBA 2.Hs0* PEE CCE IS i ' | | ' ' A Select to Draw \ 1 | ' ' ' '

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Asked by: Rahul
Created at: 2025-11-15 09:03:23

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## Step-by-Step Solution ### Step 1: Reaction with mCPBA **Explanation:** mCPBA (meta-chloroperbenzoic acid) is a peroxy acid commonly used to convert alkenes into epoxides via **epoxidation**. The double bond in the starting compound is converted into an epoxide (a three-membered cyclic ether). **Intermediate formed:** - The six-carbon chain with an epoxide at the position where the double bond was. --- ### Step 2: Treatment with H₃O⁺ **Explanation:** Acidic hydrolysis (H₃O⁺) of an epoxide leads to **anti dihydroxylation** (opening of the epoxide ring to form a trans-1,2-diol). Water attacks the more substituted carbon of the epoxide under acidic conditions. **Final Product:** - The six-carbon chain now has two hydroxyl (OH) groups on adjacent carbons (where the double bond initially was), added in an anti (trans) fashion. --- ## Final Answer: **The product is trans-2,3-hexanediol.** Here’s the structure: ``` OH OH | | CH3-CH-CH-CH2-CH2-CH3 ``` - Hydroxyl groups are on carbons 2 and 3 (trans to each other). --- **Summary:** 1. **mCPBA:** Alkene → Epoxide 2. **H₃O⁺:** Epoxide → trans-1,2-diol (trans-2,3-hexanediol) Let me know if you need the structure drawn!

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