VIPSolutionsgive answer in 2 step with explanation at the end of each step and final answer at the end:Organic Chemis 1 Old Bam Questions crea [ rvadamt agent prods hpe | Be; | ¢ a XY on GH 1. Hg(OACl, HO, THE IT ® ou 2 H;S0, HO [Ll & = Ld o CHLCH;CH CHC ZCH. LMT en Bh 2. H;05. H;0. NaOH [J " Qa a= 4 on or mom 2. HO", HO om rl 1. Nat, NH, or AER
Question:
give answer in 2 step with explanation at the end of each step and final answer at the end:
Organic Chemis 1 Old Bam Questions crea
[ rvadamt agent prods hpe |
Be; | ¢
a XY
on
GH 1. Hg(OACl, HO, THE
IT
®
ou
2 H;S0, HO
[Ll
& =
Ld
o
CHLCH;CH CHC ZCH. LMT
en Bh 2. H;05. H;0. NaOH
[J "
Qa a= 4
on
or mom
2. HO", HO
om
rl 1. Nat, NH,
or AER
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Asked by: Rahul
Created at: 2025-11-14 15:05:28
Asked by: Rahul
Created at: 2025-11-14 15:05:28
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Let's solve each problem in **2 steps** with explanations after each step, and provide the final answer at the end.
---
### (e)
**Step 1:**
**Identify the reaction type:** Br₂ in CH₂Cl₂ is an electrophilic addition to an alkene (halogenation).
**Step 2:**
**Determine the reactant:**
The product is a dibromide with Br atoms added anti to each other across a double bond. The product shown is 2,3-dibromobutane, so the reactant must be 2-butene.
**Final Answer:**
- **Reactant:** 2-butene (CH₃-CH=CH-CH₃)
- **Type:** Halogenation of alkene
---
### (f)
**Step 1:**
**Identify the reaction type:** Oxymercuration-demercuration (Markovnikov hydration of alkene).
**Step 2:**
**Predict the product:**
The double bond is between C2 and C3 in 3-methyl-2-pentene. Water adds so that OH goes to the more substituted carbon (C3).
**Final Answer:**
- **Product:** 3-methyl-3-pentanol
- **Type:** Oxymercuration-demercuration (Markovnikov hydration)
---
### (g)
**Step 1:**
**Identify the reaction type:** Epoxidation followed by acid-catalyzed ring opening (anti dihydroxylation).
**Step 2:**
**Predict the product:**
Cyclohexene reacts to form a trans-1,2-diol (trans-cyclohexane-1,2-diol).
**Final Answer:**
- **Product:** trans-cyclohexane-1,2-diol
- **Type:** Anti dihydroxylation
---
### (h)
**Step 1:**
**Identify the reaction type:** Catalytic hydrogenation.
**Step 2:**
**Predict the product:**
The double bond in 1,2-dimethylcyclopentene is reduced to give 1,2-dimethylcyclopentane.
**Final Answer:**
- **Product:** 1,2-dimethylcyclopentane
- **Type:** Catalytic hydrogenation
---
### (i)
**Step 1:**
**Identify the reaction type:** Hydroboration-oxidation (anti-Markovnikov hydration of alkyne).
**Step 2:**
**Predict the product:**
1-pentyne forms pentanal (since it is a terminal alkyne).
**Final Answer:**
- **Product:** Pentanal
- **Type:** Hydroboration-oxidation (anti-Markovnikov hydration)
---
### (j)
**Step 1:**
**Identify the reaction type:** Syn dihydroxylation (using OsO₄ or KMnO₄).
**Step 2:**
**Predict the product:**
Cyclohexene forms cis-1,2-cyclohexanediol.
**Final Answer:**
- **Product:** cis-1,2-cyclohexanediol
- **Type:** Syn dihydroxylation
---
### (k)
**Step 1:**
**Identify the reaction type:** Oxidative cleavage with hot KMnO₄.
**Step 2:**
**Predict the product:**
Toluene is oxidized to benzoic acid.
**Final Answer:**
- **Product:** Benzoic acid
- **Type:** Oxidative cleavage/oxidation
---
### (l)
**Step 1:**
**Identify the reaction type:** Alkylation of terminal alkyne (acetylide anion formation and alkylation).
**Step 2:**
**Predict the product:**
Phenylacetylene reacts with NaNH₂ to form the acetylide anion, which then reacts with CH₃Br to give 1-phenyl-1-butyne.
**Final Answer:**
- **Product:** 1-phenyl-1-butyne
- **Type:** Alkylation of terminal alkyne
---
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