VIPSolutionsgive answer in 2 step with explanation at the end of each step and final answer at the end:6. Convert he Fischer Prosctions nto Bonne drawing, Determine the Ror S contrationof ach streacete, , ME CHOH oo + NT Sion on 3 wofh Com 7. dent th owing aster cis, ros, of nthr. ANN (NI Pe Se os 5. 1a malecle has mull chil centr, thenall of Hs chil centers must be verted to generate its enantiomer. With this in mind, label each chiral center with an asterisk (*) +20 han dr he aoamomer of th molecu. condensed scr o breton ous fora uncon rou alll rou, we ot As bonne frm In You enaniomer srctre coe @ TT ee
Question:
give answer in 2 step with explanation at the end of each step and final answer at the end:
6. Convert he Fischer Prosctions nto Bonne drawing, Determine the Ror S
contrationof ach streacete,
, ME
CHOH
oo
+ NT
Sion
on
3 wofh
Com
7. dent th owing aster cis, ros, of nthr.
ANN (NI Pe Se os
5. 1a malecle has mull chil centr, thenall of Hs chil centers must be verted to
generate its enantiomer. With this in mind, label each chiral center with an asterisk (*)
+20 han dr he aoamomer of th molecu. condensed scr o breton
ous fora uncon rou alll rou, we ot As bonne frm In You
enaniomer srctre
coe @
TT ee
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Asked by: Roshan
Created at: 2025-11-07 18:38:34
Asked by: Roshan
Created at: 2025-11-07 18:38:34
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Let's break down the answers step-by-step as requested.
---
## **6. Convert Fischer Projections into Bond-Line Drawing and Assign R/S**
### **Step 1: Convert Fischer to Bond-Line**
#### **1.**
- The Fischer projection shows:
- Top: CHO (Aldehyde)
- Bottom: CH₂OH (Primary alcohol)
- Left: H
- Right: OH
**Bond-line:**
```
HOCH₂-CH(OH)-CHO
```
#### **2.**
- The Fischer projection shows:
- Top: CHO
- Bottom: CH₂OH
- Left: HO (at C2), H (at C3)
- Right: H (at C2), OH (at C3)
**Bond-line:**
```
HOCH₂-CH(OH)-CH(OH)-CHO
```
#### **3.**
- The Fischer projection shows:
- Top: CH₃
- Bottom: CO₂H (Carboxylic Acid)
- Left: HO
- Right: H
**Bond-line:**
```
HO-CH(CH₃)-CO₂H
```
**Explanation:**
In a Fischer projection, horizontal lines point out of the plane (towards you) and vertical lines point away from you.
---
### **Step 2: Assign R/S Configuration**
#### **1.**
- Assign priorities (CHO > OH > CH₂OH > H).
- Lowest priority group (H) is on the horizontal, so reverse the result after determining the order.
- Counting: CHO (1), OH (2), CH₂OH (3), H (4)
- Order: 1 → 2 → 3 is **counterclockwise** (S), but since H is on the horizontal, **actual configuration is R**.
#### **2.**
- Two stereocenters to assign.
- **C2:** (CHO > OH > CH₂OH > H)
- H is horizontal, so reverse.
- 1 (CHO) → 2 (OH) → 3 (CH₂OH): counterclockwise (S), so actual is **R**.
- **C3:** (CHO > OH > CH₂OH > H)
- H is horizontal, so reverse.
- 1 (CHO) → 2 (OH) → 3 (CH₂OH): clockwise (R), so actual is **S**.
#### **3.**
- Assign priorities (CO₂H > OH > CH₃ > H)
- H is on the right (horizontal), so reverse the result.
- 1 (CO₂H) → 2 (OH) → 3 (CH₃): clockwise (R), so actual is **S**.
**Explanation:**
Assign priorities based on atomic number. If the lowest priority is on a horizontal (Fischer), reverse your R/S assignment.
---
### **Final Answer for Question 6**
1. **Bond-Line:** HOCH₂-CH(OH)-CHO, **Configuration:** R
2. **Bond-Line:** HOCH₂-CH(OH)-CH(OH)-CHO, **Configurations:** C2 = R, C3 = S
3. **Bond-Line:** HO-CH(CH₃)-CO₂H, **Configuration:** S
---
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