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give answer in 2 step with explanation at the end of each step and final answer at the end:w § gs Ad Jd = x F a fii T Hi i HAH : i O HEHE is / HHL § = {HE 8H] hn HEH EE: fn i = RE 2 lig Eo Li E i I] il id Ee H lt

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give answer in 2 step with explanation at the end of each step and final answer at the end:Uploaded Imagew § gs Ad Jd = x F a fii T Hi i HAH : i O HEHE is / HHL § = {HE 8H] hn HEH EE: fn i = RE 2 lig Eo Li E i I] il id Ee H lt

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Asked by: Roshan
Created at: 2025-11-07 18:36:24

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# Stepwise: Dihydroxylation Mechanism ## **Step 1: Draw a Reasonable Mechanism for cis-Dihydroxylation with Osmium Tetroxide (OsO₄)** **Mechanism:** 1. **Formation of Cyclic Osmate Ester:** The alkene reacts with OsO₄ in a concerted [3+2] cycloaddition to form a cyclic osmate ester intermediate. - This step occurs in a *syn* manner, so both oxygens add to the same face of the alkene. **Explanation:** OsO₄ approaches the alkene, and the π electrons of the double bond interact with the osmium to form a five-membered ring intermediate. This locks both oxygens on the same side. --- ## **Step 2: Hydrolysis of the Osmate Ester to Give the cis-Diol** **Mechanism:** 2. **Hydrolysis (Work-up Step):** The cyclic osmate ester is hydrolyzed (often with H₂O₂ or water), breaking the Os–O bonds and releasing the *cis*-diol, while OsO₄ is regenerated. **Explanation:** Water (or another oxidant) cleaves the osmate ester, resulting in vicinal diol formation with both hydroxyl groups on the same side (*syn* addition, giving the *cis*-diol). --- ## **Final Answer** - The overall mechanism with OsO₄ gives the **cis-diol** via a syn addition mechanism involving a cyclic osmate ester intermediate, followed by hydrolysis to yield the cis (syn) diol product. --- **Summary Diagram:** ``` Step 1: Alkene + OsO₄ → Cyclic osmate ester (syn addition) Step 2: Cyclic osmate ester + H₂O₂/H₂O → cis-Diol + regenerated OsO₄ ``` **Key Point:** Both oxygens add to the same side of the double bond, giving a cis-diol.

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Asked by: Roshan
Created at: 2025-11-07 18:36:50

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# Dihydroxylation Mechanism Using Osmium Tetroxide ## **Step 1: Formation of Cyclic Osmate Ester** **Mechanism:** 1. **Cyclic Osmate Ester Formation:** The alkene undergoes a reaction with OsO₄, resulting in the formation of a cyclic osmate ester intermediate through a concerted [3+2] cycloaddition. - The addition occurs in a *syn* manner, meaning both oxygen atoms from OsO₄ add to the same side of the alkene. **Explanation:** In this step, OsO₄ approaches the alkene, and the π electrons from the double bond interact with osmium. This interaction results in the formation of a five-membered cyclic intermediate, ensuring that both oxygens are added to the same face of the alkene. --- ## **Step 2: Hydrolysis to Produce cis-Diol** **Mechanism:** 2. **Hydrolysis of Cyclic Osmate Ester:** The cyclic osmate ester is hydrolyzed, typically using water or hydrogen peroxide, which cleaves the Os–O bonds and results in the formation of a *cis*-diol while regenerating OsO₄. **Explanation:** In this hydrolysis step, water or another oxidizing agent breaks the bonds in the osmate ester. This results in the formation of a vicinal diol with both hydroxyl groups positioned on the same side of the original alkene, confirming that a syn addition occurred, leading to the formation of the cis-diol. --- ## **Final Answer** - The mechanism results in the formation of a **cis-diol** through a syn addition mechanism. The process involves: - Step 1: Alkene reacts with OsO₄ to form a cyclic osmate ester. - Step 2: Hydrolysis of the cyclic osmate ester yields the cis-diol. --- **Summary Diagram:** ``` Step 1: Alkene + OsO₄ → Cyclic osmate ester (syn addition) Step 2: Cyclic osmate ester + H₂O/H₂O₂ → cis-Diol + regenerated OsO₄ ``` **Key Point:** Both hydroxyl groups are added to the same side of the double bond, resulting in a cis-diol.

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