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give answer in 2 step with explanation at the end of each step and final answer at the end:6.7. Rewrite the function entropy on page 35 without any loops using sort, diff, find, and (perhaps) sum. [| 3.5. Suppose a data source produces a series of characters drawn from a set of M distinct symbols. If symbol k is produced with probability py. the first-order entropy of the source is defined as M Hy= => nm logy pk. k=1 Essentially Hj is the number of bits needed per symbol to encode a long mes- sage: that is, it measures the amount of information content, and therefore the potential success of compression strategies. The value Hy = 0 corre- sponds to the case of only one symbol being produced—no information— while if all M symbols have equal probability. then Hy = log, M. Write a function [H,M] = entropy (v) that computes entropy for a vector v. The probabilities should be computed empirically by finding the unique entries (using unique), then counting the occurrences of each symbol and dividing by the length of v. Try your function on some built-in image data by entering load clown, v = X(:);.

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give answer in 2 step with explanation at the end of each step and final answer at the end:Uploaded Image6.7. Rewrite the function entropy on page 35 without any loops using sort, diff, find, and (perhaps) sum. [| 3.5. Suppose a data source produces a series of characters drawn from a set of M distinct symbols. If symbol k is produced with probability py. the first-order entropy of the source is defined as M Hy= => nm logy pk. k=1 Essentially Hj is the number of bits needed per symbol to encode a long mes- sage: that is, it measures the amount of information content, and therefore the potential success of compression strategies. The value Hy = 0 corre- sponds to the case of only one symbol being produced—no information— while if all M symbols have equal probability. then Hy = log, M. Write a function [H,M] = entropy (v) that computes entropy for a vector v. The probabilities should be computed empirically by finding the unique entries (using unique), then counting the occurrences of each symbol and dividing by the length of v. Try your function on some built-in image data by entering load clown, v = X(:);.

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Asked by: Rahulkumar
Created at: 2025-10-07 20:22:08

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## Step 1: Find Unique Symbols and Probabilities First, get the unique symbols and their probabilities using `unique`, `diff`, and `find` (without any loops): ```matlab % v is the input vector [s, ~, idx] = unique(v); % Unique symbols and their indices M = numel(s); % Number of unique symbols count = diff([; find(diff(sort(idx))); numel(idx)]); % Count occurrences p = count / numel(v); % Probability of each symbol ``` **Explanation:** - `unique(v)` finds the unique symbols and assigns each entry in `v` a label (index). - Sorting `idx` and then using `diff` and `find` allows us to count the number of occurrences of each symbol without loops. - Dividing by the length of `v` gives the empirical probabilities. --- ## Step 2: Compute Entropy Now, calculate the entropy using the probabilities: ```matlab H = -sum(p .* log2(p)); % Entropy formula ``` **Explanation:** - This applies the entropy formula: \( H_1 = -\sum_{k=1}^{M} p_k \log_2 p_k \). - `sum` is allowed (as per instructions). --- ## Final Answer: Complete Function ```matlab function [H, M] = entropy(v) [~, ~, idx] = unique(v); M = max(idx); count = diff([; find(diff(sort(idx))); numel(idx)]); p = count / numel(v); H = -sum(p .* log2(p)); end ``` **This function computes the entropy without using any loops, and uses only `sort`, `diff`, `find`, and `sum` as required.**

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Solve please 6.7part and then solve 3.5part

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Asked by: Rahulkumar
Created at: 2025-10-07 20:24:04

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# Solution to Problem 6.7 ## Step 1: Find Unique Symbols and Probabilities To calculate the empirical probabilities of each symbol in the input vector \( v \), we utilize the `unique`, `diff`, and `find` functions without any loops. ```matlab % v is the input vector [s, ~, idx] = unique(v); % Get unique symbols and their indices M = numel(s); % Count of unique symbols count = diff([0; find(diff(sort(idx))); numel(idx)]); % Count occurrences p = count / numel(v); % Calculate probability for each unique symbol ``` **Explanation:** - The `unique` function retrieves unique symbols and their corresponding indices. - The `sort` function organizes the indices to facilitate counting with `diff`. - The `diff` and `find` operations determine the count of each symbol, which is then normalized by the total length of vector \( v \) to derive the probabilities. --- ## Step 2: Compute Entropy Next, we compute the entropy \( H \) using the empirical probabilities calculated in Step 1. ```matlab H = -sum(p .* log2(p)); % Entropy calculation ``` **Explanation:** - The entropy formula is applied here: \[ H = -\sum_{k=1}^{M} p_k \log_2 p_k \] - The `sum` function aggregates the contributions of each symbol's probability to the total entropy. --- ## Final Answer: Complete Function for 6.7 ```matlab function [H, M] = entropy(v) [s, ~, idx] = unique(v); % Unique symbols M = numel(s); % Number of unique symbols count = diff([0; find(diff(sort(idx))); numel(idx)]); % Count occurrences p = count / numel(v); % Compute probabilities H = -sum(p .* log2(p)); % Calculate entropy end ``` # Solution to Problem 3.5 The problem states that the first-order entropy \( H \) for a set of \( M \) distinct symbols, where symbol \( k \) is produced with probability \( p_k \), is defined as: \[ H = -\sum_{k=1}^{M} p_k \log_2 p_k \] ## Step 1: Define the Symbols and Probabilities Given \( M \) distinct symbols, we compute their probabilities \( p_k \) empirically from the data source. ## Step 2: Calculate the Entropy Using the formula for entropy, we can directly compute it based on the observed probabilities from our data source. **Entropy Interpretation:** - \( H = 0 \) indicates no uncertainty (only one symbol). - If all symbols have equal probability, \( H = \log_2(M) \). --- ## Final Answer for 3.5 The entropy can be computed with the same function defined in 6.7, replacing \( v \) with the data source that generates the symbols. The function will yield the entropy based on the empirical probabilities derived from the unique symbols.

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