give answer in 2 step with explanation at the end of each step and final answer at the end:(d)943 (£005) X {[62 (£02) X 107] + [4.1 (£01) X 107]} = 2
Question:
give answer in 2 step with explanation at the end of each step and final answer at the end:
(d)943 (£005) X {[62 (£02) X 107] + [4.1 (£01) X 107]} = 2
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Asked by: Pagal
Created at: 2025-09-07 03:10:16
Asked by: Pagal
Created at: 2025-09-07 03:10:16
Final Answer:
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Let's solve the given expression step by step, including uncertainties:
Given:
\[
9.43 (\pm 0.05) \times \left[ (6.2 \pm 0.2) \times 10^{-3} + (4.1 \pm 0.1) \times 10^{-3} \right]
\]
---
### **Step 1: Add the two numbers inside the bracket (considering their uncertainties)**
\[
(6.2 \pm 0.2) \times 10^{-3} + (4.1 \pm 0.1) \times 10^{-3}
\]
Add the central values:
\[
6.2 + 4.1 = 10.3
\]
Add the uncertainties (since uncertainties add for addition/subtraction):
\[
0.2 + 0.1 = 0.3
\]
So,
\[
(10.3 \pm 0.3) \times 10^{-3}
\]
**Explanation:**
When adding quantities, their uncertainties are also added.
---
### **Step 2: Multiply by 9.43 (±0.05) and calculate the resulting uncertainty**
Now multiply:
\[
9.43 (\pm 0.05) \times (10.3 \pm 0.3) \times 10^{-3}
\]
Multiply the central values:
\[
9.43 \times 10.3 = 97.129
\]
Calculate the relative (fractional) uncertainties and add for multiplication:
- For \(9.43\): \(\frac{0.05}{9.43} \approx 0.0053\)
- For \(10.3\): \(\frac{0.3}{10.3} \approx 0.0291\)
- Total relative uncertainty: \(0.0053 + 0.0291 = 0.0344\)
So, the absolute uncertainty in the product is:
\[
0.0344 \times 97.129 \approx 3.34
\]
So the answer is:
\[
(97.1 \pm 3.3) \times 10^{-3}
\]
Or, writing with the same power of ten:
\[
(0.097 \pm 0.003)\ (\text{rounded to 3 significant digits, matching uncertainties})
\]
---
## **Final Answer:**
\[
\boxed{(0.097 \pm 0.003)}
\]
**All steps included calculation and propagation of uncertainties as required.**
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