give answer in 2 step with explanation at the end of each step and final answer at the end:Problem 2 (Non-integral fiow). In class we mentioned that Ford Fulkerson
A TR
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Cis large constant (e.g. 10%), and fis the solution to the quadratic equation
= 1—. Define the paths (in the residual graph):
Wrait
[PUPP
Orr
Orin
Sopp von Ford Blond bpp 1 oe te loving
fe 1 ls ms hh 0nd fw he he nc
DBD ane sn te
,
_________________________________
—
(0 Ets on he fo ie xen ne te ce of ee
Erbin hon he fon vie cle ee
oy wl te
Cont, pds aa te ws ko ve
fe fn? Nt kr hors wih nth Fk cn
shuld wd fox dong bn or ete
Question:
give answer in 2 step with explanation at the end of each step and final answer at the end:Problem 2 (Non-integral fiow). In class we mentioned that Ford Fulkerson
A TR
st te ir pl th or
’, [4 4
hd
Cis large constant (e.g. 10%), and fis the solution to the quadratic equation
= 1—. Define the paths (in the residual graph):
Wrait
[PUPP
Orr
Orin
Sopp von Ford Blond bpp 1 oe te loving
fe 1 ls ms hh 0nd fw he he nc
DBD ane sn te
,
_________________________________
—
(0 Ets on he fo ie xen ne te ce of ee
Erbin hon he fon vie cle ee
oy wl te
Cont, pds aa te ws ko ve
fe fn? Nt kr hors wih nth Fk cn
shuld wd fox dong bn or ete
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Asked by: Test User 100194
Created at: 2025-05-07 22:44:55
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Let's answer the questions step by step as requested:
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### Step 1: **(a) Explain how the flow value evolves over the course of this sequence. Does the flow value converge to the max flow?**
#### **Explanation:**
- **Initial Path (A):**
The first path used is \( A: s \to a \to b \to t \).
The bottleneck edge along this path is the edge with capacity \( \varphi \) (the edge \( a \to b \)), so \( \varphi \) units of flow are sent along this path.
- **Subsequent Paths (BCBD):**
The next paths repeatedly used are \( BCBD: s \to b \to c \to b \to d \to t \) (looping through \( b \) and \( c \)).
Each time, the amount of flow that can be pushed along each \( BCBD \) path is a fraction of what was pushed before, due to the non-integer residual capacities left after each augmentation. Specifically, the residual capacity decreases by a factor of \( \varphi \) each time because of how the cycles and capacities interact. This is similar to a geometric series:
- After the first \( BCBD \), the flow remaining on the critical edges is multiplied by \( \varphi \).
- After \( k \) augmentations, the total added flow is \( \varphi + \varphi^2 + \varphi^3 + \ldots + \varphi^k \).
- **Does it converge?**
- Yes, the total flow converges to a limit, since it is a geometric series with ratio \( \varphi < 1 \).
- **However, it never actually reaches the true max flow in a finite number of steps**, because the sum \( \varphi + \varphi^2 + \varphi^3 + \ldots \) approaches a limit but never attains it exactly.
#### **Conclusion after Step 1:**
The flow value increases by a geometric series and converges to a value less than the true max flow, so **the Ford-Fulkerson algorithm may not terminate on this graph with non-integer capacities**.
---
### Step 2: **(b) Could we have picked a different set of paths to use so that we indeed find the max flow? Write a rule for choosing which path Ford-Fulkerson should use in every iteration so that it does find the correct max flow for this particular graph.**
#### **Explanation:**
- The issue with the sequence \( A, BCBD, BCBD, ... \) is that it always chooses paths that push smaller and smaller amounts of flow due to the non-integer capacities and cycles, never saturating the edges that would help us reach max flow.
- **If, instead, we always pick the augmenting path with the largest available residual capacity (i.e., the "fattest" path or the path that can carry the most flow from \( s \) to \( t \) in the current residual graph),** we can guarantee that the number of augmentations is finite and the algorithm will terminate with the correct max flow.
- This approach is called the **Edmonds-Karp algorithm**, which always selects the shortest augmenting path (in terms of number of edges), or more generally, always picks the path that maximizes the bottleneck capacity in each iteration.
#### **Rule for Path Selection:**
- **At each step, choose the augmenting path from \( s \) to \( t \) in the residual graph with the largest possible bottleneck (minimum) capacity.**
- Alternatively, always pick the shortest augmenting path if all edge capacities are positive.
#### **Conclusion after Step 2:**
**Yes, by always choosing the path with the largest available capacity (or the shortest path), Ford-Fulkerson will terminate with the correct max flow.**
---
## **Final Answer**
---
### **(a)**
The flow value increases as a geometric series because each augmenting path (after the first) adds a smaller fraction of flow due to the non-integer capacities. The total flow approaches a limit but never reaches the true max flow in a finite number of steps. **Thus, the value converges, but Ford-Fulkerson does not terminate with the max flow for this sequence of paths.**
### **(b)**
Yes, if we always pick the augmenting path with the largest available capacity (the path with the largest bottleneck), **Ford-Fulkerson will terminate with the correct max flow.** The rule is:
**At each iteration, choose the augmenting path from \( s \) to \( t \) in the residual graph with the largest possible bottleneck capacity.**
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