give answer in 2 step with explanation at the end of each step and final answer at the end:1. (2 pts) Find the equations of the cross-sections of z = y? — zy with fixed z = 0,1, and fixed = 0,1. Sketch them in the appropriate coordinate planes.
Question:
give answer in 2 step with explanation at the end of each step and final answer at the end:
1. (2 pts) Find the equations of the cross-sections of z = y? — zy with fixed z = 0,1, and fixed
= 0,1. Sketch them in the appropriate coordinate planes.
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Asked by: Babu
Created at: 2025-07-13 17:57:32
Asked by: Babu
Created at: 2025-07-13 17:57:32
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Let's solve the problem step by step:
---
### **Step 1: Cross-sections with fixed \(x = 0, 1\)**
Given: \(z = y^2 - xy\)
- For \(x = 0\):
Substitute \(x = 0\) into the equation:
\[
z = y^2 - (0)y = y^2
\]
**Explanation:** This is a parabola in the \(yz\)-plane.
- For \(x = 1\):
Substitute \(x = 1\) into the equation:
\[
z = y^2 - (1)y = y^2 - y
\]
**Explanation:** This is also a parabola in the \(yz\)-plane, but shifted.
---
### **Step 2: Cross-sections with fixed \(y = 0, 1\)**
- For \(y = 0\):
Substitute \(y = 0\) into the equation:
\[
z = (0)^2 - x(0) = 0
\]
**Explanation:** This is the line \(z = 0\) in the \(xz\)-plane.
- For \(y = 1\):
Substitute \(y = 1\) into the equation:
\[
z = (1)^2 - x(1) = 1 - x
\]
**Explanation:** This is a straight line with a slope of \(-1\) in the \(xz\)-plane.
---
### **Final Answer:**
- For fixed \(x = 0\): \(z = y^2\) (parabola in \(yz\)-plane)
- For fixed \(x = 1\): \(z = y^2 - y\) (parabola in \(yz\)-plane)
- For fixed \(y = 0\): \(z = 0\) (line in \(xz\)-plane)
- For fixed \(y = 1\): \(z = 1 - x\) (line in \(xz\)-plane)
You can sketch these by plotting the corresponding equations in the \(yz\)-plane for fixed \(x\), and in the \(xz\)-plane for fixed \(y\).
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