give answer in 2 step with all parts explanation at the end of each step and final answer at the end:y koordinatlarini ve x ckseni [rte Shed wow . Ere Fw
Question:
give answer in 2 step with all parts explanation at the end of each step and final answer at the end:
y koordinatlarini ve x ckseni
[rte
Shed
wow . Ere
Fw
This is AI generated Response.
Asked by: Rahul
Created at: 2025-11-30 03:12:56
Asked by: Rahul
Created at: 2025-11-30 03:12:56
Final Answer:
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# Step 1: **Find the Coordinates \((x_m, y_m)\) of the Shaded Area**
## **Explanation:**
The shaded region is inside a square of side \(2r\), bounded by:
- The square (from \(x=\) to \(x=2r\), \(y=\) to \(y=2r\))
- The quarter circle (center at \((r, r)\), radius \(r\))
- The triangle below the quarter circle
The centroid \((x_m, y_m)\) of the shaded area is given:
\[
x_m = y_m = \frac{4r}{3\pi}
\]
(As given in the problem.)
### **Why?**
For a quarter circle of radius \(r\), the centroid from the straight edges is \(\frac{4r}{3\pi}\). Since the shaded area is the quarter circle minus the triangle, and the centroid formula provided matches the quarter circle, we use this value.
---
# Step 2: **Find the Volume Formed by Rotating the Shaded Area Around the \(x\)-axis**
## **Explanation:**
The shaded area is a **quarter circle** (area \(A_1\)) **minus a triangle** (area \(A_2\)).
### **Area Calculations:**
- **Quarter circle:**
\[
A_1 = \frac{1}{4} \pi r^2
\]
- **Triangle (right triangle with legs \(r\)):**
\[
A_2 = \frac{1}{2} r \cdot r = \frac{r^2}{2}
\]
- **Shaded area:**
\[
A = A_1 - A_2 = \frac{1}{4} \pi r^2 - \frac{r^2}{2}
\]
### **Volume of Revolution (about \(x\)-axis):**
When the shaded area is revolved about the \(x\)-axis, the volume is:
\[
V = \text{Shaded Area} \times (\text{Circumference traced by centroid})
\]
The centroid's distance from the x-axis is \(y_m\), so the path traced is a circle of radius \(y_m\):
\[
V = (\text{Shaded Area}) \times (2\pi y_m)
\]
Plugging in the values:
- \(y_m = \frac{4r}{3\pi}\)
- \(\pi = 3\) (as given)
Calculate the shaded area:
\[
A = \frac{1}{4} \cdot 3 \cdot r^2 - \frac{r^2}{2} = \frac{3}{4} r^2 - \frac{1}{2} r^2 = \frac{3-2}{4} r^2 = \frac{1}{4} r^2
\]
Now plug into the volume formula:
\[
V = \frac{1}{4} r^2 \cdot 2\pi \cdot \frac{4r}{3\pi}
\]
\[
V = \frac{1}{4} r^2 \cdot \frac{8r}{3}
\]
\[
V = \frac{8}{12} r^3 = \frac{2}{3} r^3
\]
---
# **Final Answer**
- **Centroid coordinates:** \(x_m = y_m = \frac{4r}{3\pi}\)
- **Volume of solid formed:**
\[
\boxed{V = \frac{2}{3} r^3}
\]
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