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RS. (20 points) The following two way table (in excel file HW 11 in CANVAS) gives data for 2X2 factorial experiment. (a) How many factors do the data have? (b) How many levels do each factor have? (¢) Determine the number of treatments used? (d) Construct an ANOVA for this experiment and determine whether if there is interaction between the two factors or not? Use a = 0.05 Ros B1 B2 Al 29.6 47.3 Al 35.2 42.1 A2 12.9 28.4 A2 17.6 22.7

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Uploaded ImageRS. (20 points) The following two way table (in excel file HW 11 in CANVAS) gives data for 2X2 factorial experiment. (a) How many factors do the data have? (b) How many levels do each factor have? (¢) Determine the number of treatments used? (d) Construct an ANOVA for this experiment and determine whether if there is interaction between the two factors or not? Use a = 0.05 Ros B1 B2 Al 29.6 47.3 Al 35.2 42.1 A2 12.9 28.4 A2 17.6 22.7

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Asked by: Test User 100193
Created at: 2025-05-10 17:42:02

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Let's answer each part step by step: ### (a) How many factors do the data have? **Answer:** There are **2 factors** in the data (Factor A and Factor B). --- ### (b) How many levels do each factor have? **Answer:** - **Factor A:** 2 levels (A1, A2) - **Factor B:** 2 levels (B1, B2) --- ### (c) Determine the number of treatments used? **Answer:** - Each unique combination of a level of Factor A and a level of Factor B is a treatment. - There are 2 levels for Factor A × 2 levels for Factor B = **4 treatments**. --- ### (d) Construct an ANOVA for this experiment and determine whether there is interaction between the two factors or not. Use α = 0.05. #### Step 1: Tabulate the Data | | B1 | B2 | |----------|------|------| | **A1** | 29.6 | 47.3 | | **A1** | 35.2 | 42.1 | | **A2** | 12.9 | 28.4 | | **A2** | 17.6 | 22.7 | #### Step 2: Layout the Data for ANOVA - A1B1: 29.6, 35.2 - A1B2: 47.3, 42.1 - A2B1: 12.9, 17.6 - A2B2: 28.4, 22.7 #### Step 3: Calculate Means - **Grand Mean (GM):** \( GM = \frac{29.6 + 35.2 + 47.3 + 42.1 + 12.9 + 17.6 + 28.4 + 22.7}{8} = \frac{235.8}{8} = 29.475 \) - **Means by group:** - A1B1: (29.6 + 35.2)/2 = 32.4 - A1B2: (47.3 + 42.1)/2 = 44.7 - A2B1: (12.9 + 17.6)/2 = 15.25 - A2B2: (28.4 + 22.7)/2 = 25.55 #### Step 4: ANOVA Table For a 2x2 factorial, you would calculate sums of squares for: - Factor A - Factor B - Interaction (A × B) - Error **Due to space, I'll outline the process (you can do calculations in Excel or by hand):** 1. **SS_Total:** Sum of squared differences from the grand mean. 2. **SS_A:** Difference between the means of A1 and A2, adjusted by the number of observations. 3. **SS_B:** Difference between the means of B1 and B2, adjusted by the number of observations. 4. **SS_AB (interaction):** Difference between cell means and what would be expected from A and B alone. 5. **SS_Error:** Difference between each observation and its cell mean. **Degrees of freedom:** - df_A = (levels of A - 1) = 1 - df_B = (levels of B - 1) = 1 - df_AB = (levels of A - 1) × (levels of B - 1) = 1 - df_Error = N - (number of groups) = 8 - 4 = 4 **Calculate mean squares and F-values:** - MS = SS / df - F = MS_effect / MS_error **Compare F values to critical value at α = 0.05 for df1 = 1, df2 = 4** #### Step 5: Conclusion If the F value for interaction is **greater** than the critical value (or p-value < 0.05), there **is significant interaction**. Otherwise, there is **no significant interaction**. Let me know if you want the explicit ANOVA calculations and I can compute them step by step!

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Give ANOVA calculation

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Asked by: Test User 100193
Created at: 2025-05-11 10:02:18

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Let's perform the detailed ANOVA calculations step by step for the given data. --- ### Step 1: Data Recap | **A / B** | **B1** | **B2** | **Row Mean** | |------------|---------|---------|--------------| | **A1** | 29.6 | 47.3 | (29.6+47.3)/2 = 38.45 | | **A1** | 35.2 | 42.1 | (35.2+42.1)/2 = 38.65 | | **A2** | 12.9 | 28.4 | (12.9+28.4)/2 = 20.65 | | **A2** | 17.6 | 22.7 | (17.6+22.7)/2 = 20.15 | ### Step 2: Calculate Grand Mean (GM) \[ GM = \frac{29.6 + 47.3 + 35.2 + 42.1 + 12.9 + 28.4 + 17.6 + 22.7}{8} = \frac{238.8}{8} = 29.85 \] ### Step 3: Calculate Main Effect Means - **A1 mean:** \[ \bar{A1} = \frac{29.6 + 47.3 + 35.2 + 42.1}{4} = \frac{154.2}{4} = 38.55 \] - **A2 mean:** \[ \bar{A2} = \frac{12.9 + 28.4 + 17.6 + 22.7}{4} = \frac{81.6}{4} = 20.4 \] - **B1 mean:** \[ \bar{B1} = \frac{29.6 + 35.2 + 12.9 + 17.6}{4} = \frac{95.3}{4} = 23.825 \] - **B2 mean:** \[ \bar{B2} = \frac{47.3 + 42.1 + 28.4 + 22.7}{4} = \frac{140.5}{4} = 35.125 \] ### Step 4: Calculate Sum of Squares Total observations \( n = 8 \). --- ### Sum of Squares Total (SS\_Total): \[ SS_{Total} = \sum (Y_{ij} - GM)^2 \] Compute each term: \[ \begin{aligned} (29.6 - 29.85)^2 &= 0.0625 \\ (47.3 - 29.85)^2 &= 301.5225 \\ (35.2 - 29.85)^2 &= 28.9225 \\ (42.1 - 29.85)^2 &= 147.1225 \\ (12.9 - 29.85)^2 &= 288.1225 \\ (28.4 - 29.85)^2 &= 2.1025 \\ (17.6 - 29.85)^2 &= 147.1225 \\ (22.7 - 29.85)^2 &= 50.1225 \\ \end{aligned} \] Sum: \[ SS_{Total} = 0.0625 + 301.5225 + 28.9225 + 147.1225 + 288.1225 + 2.1025 + 147.1225 + 50.1225 = \textbf{965.04} \] --- ### Sum of Squares for Factor A (SS\_A): \[ SS_A = n_b \times \sum_{a} (\bar{A}_a - GM)^2 \] Where \( n_b = 4 \) (number of B levels per A). \[ \begin{aligned} (\bar{A1} - GM)^2 &= (38.55 - 29.85)^2 = 74.9025 \\ (\bar{A2} - GM)^2 &= (20.4 - 29.85)^2 = 91.1225 \\ \end{aligned} \] Compute: \[ SS_A = 4 \times (74.9025 + 91.1225) = 4 \times 166.025 = 664.1 \] --- ### Sum of Squares for Factor B (SS\_B): \[ SS_B = n_a \times \sum_{b} (\bar{B}_b - GM)^2 \] Where \( n_a = 4 \): \[ \begin{aligned} (\bar{B1} - GM)^2 &= (23.825 - 29.85)^2 = 36.0625 \\ (\bar{B2} - GM)^2 &= (35.125 - 29.85)^2 = 28.5225 \\ \end{aligned} \] Compute: \[ SS_B = 4 \times (36.0625 + 28.5225) = 4 \times 64.585 = 258.34 \] --- ### Sum of Squares for Interaction (SS\_AB): \[ SS_{AB} = \sum_{a,b} n_{ab} (\bar{Y}_{ab} - \bar{A}_a - \bar{B}_b + GM)^2 \] Since each cell has 2 observations (\( n_{ab} = 2 \)): Calculate each cell's deviation: \[ \begin{aligned} A1B1:\quad & \bar{Y}_{A1B1} = (29.6 + 35.2)/2 = 32.4 \\ & \text{Expected } = \bar{A1} + \bar{B1} - GM = 38.55 + 23.825 - 29.85 = 32.525 \\ & \text{Difference} = 32.4 - 32.525 = -0.125 \\ \Rightarrow & \quad (-0.125)^2 = 0.0156 \\ \text{Contribution} &= 2 \times 0.0156 = 0.0312 \\ \end{aligned} \] Similarly for other cells: - **A1B2:** \[ \bar{Y}_{A1B2} = (47.3 + 42.1)/2 = 44.7 \] Expected: \[ 38.55 + 35.125 - 29.85 = 43.825 \] Difference: \[ 44.7 - 43.825 = 0.875 \] Squared: \[ 0.875^2 = 0.7656 \] Contribution: \[ 2 \times 0.7656 = 1.5312 \] - **A2B1:** \[ \bar{Y}_{A2B1} = (12.9 + 17.6)/2 = 15.25 \] Expected: \[ 20.4 + 23.825 - 29.85 = 14.375 \] Difference: \[ 15.25 - 14.375 = 0.875 \] Squared: \[ 0.875^2 = 0.7656 \] Contribution: \[ 2 \times 0.7656 = 1.5312 \] - **A2B2:** \[ \bar{Y}_{A2B2} = (28.4 + 22.7)/2 = 25.55 \] Expected: \[ 20.4 + 35.125 - 29.85 = 25.675 \] Difference: \[ 25.55 - 25.675 = -0.125 \] Squared: \[ (-0.125)^2=0.0156 \] Contribution: \[ 2 \times 0.0156=0.0312 \] Sum all contributions: \[ SS_{AB} = 0.0312 + 1.5312 + 1.5312 + 0.0312 = \boxed{3.124} \] --- ### Sum of Squares for Error (SS\_Error): \[ SS_{Error} = SS_{Total} - SS_A - SS_B - SS_{AB} \] \[ SS_{Error} = 965.04 - 664.1 - 258.34 - 3.124 = 965.04 - 925.564 = \boxed{39.476} \] --- ### Step 5: Degrees of Freedom (df) | Effect | df | |---------|----| | A | 1 | | B | 1 | | AB | 1 | | Error | 8 - 4 = 4 | --- ### Step 6: Mean Squares (MS) \[ MS_A = \frac{SS_A}{df_A} = \frac{664.1}{1} = 664.1 \] \[ MS_B = \frac{258.34}{1} = 258.34 \] \[ MS_{AB} = \frac{3.124}{1} = 3.124 \] \[ MS_{Error} = \frac{39.476}{4} = 9.869 \] --- ### Step 7: F-Statistics \[ F_A = \frac{MS_A}{MS_{Error}} = \frac{664.1}{9.869} \approx 67.33 \] \[ F_B = \frac{258.34}{9.869} \approx 26.19 \] \[ F_{AB} = \frac{3.124}{9.869} \approx 0.317 \] ### Step 8: Critical Value at α=0.05 Using F-distribution tables for df1=1 and df2=4: - \( F_{crit} \approx 6.16 \) --- ### **Final Conclusion:** - **Factor A:** \( F \approx 67.33 \) > 6.16 → **Significant** - **Factor B:** \( F \approx 26.19 \) > 6.16 → **Significant** - **Interaction (A×B):** \( F \approx 0.317 \) < 6.16 → **Not significant** **Thus, there is no significant interaction between the factors at α=0.05.** Both factors A and B significantly affect the response independently. --- **Summary:** | Effect | F-value | Significance at α=0.05 | Conclusion | |---------------|----------|------------------------|--------------------------| | Factor A | 67.33 | Yes | Significant | | Factor B | 26.19 | Yes | Significant | | Interaction | 0.317 | No | No significant interaction| --- Let me know if you'd like further details or interpretations!

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