Let's break down the **acid-base reaction** shown in your image and clearly illustrate the electron flow (curved arrows) and the final product (eletript succinate salt). --- ## Step1: Identify and Base **Eletran** contains **terti amine** ( atom with lone), which acts a **base. - **Suic acid** is adicarboxlic acid** (two -OH groups), acts as anacid**. --- ## Step : Proton Transfer (Curved Arrows) Here’s happens: 1. **Lone pair on the nitrogen** ofiptan attacks a proton (H⁺) from one of the -COOH groups of succinic acid. 2. **Curved arrow 1:** From nitrogen lone pair to hydrogen of -COOH. 3. **Curved arrow 2:** From O-H bond of succinic acid to oxygen, forming a carboxylate anion (-COO⁻). The result: - **Eletriptan is protonated** (forms an ammonium ion, N⁺H). - **Succinic acid** loses a proton (becomes succinate anion, -COO⁻). --- ## Step 3: Draw the Final Product (Salt Formation) - **Eletriptan** is now in its **protonated (NH⁺)** form. - **Succinic acid** is now the **succinate anion** (one -COO⁻, one -COOH). - They form an **ionic salt** (eletriptan succinate). --- ## Diagram with Curved Arrows ```markdown [Eletriptan-N:] + HOOC-CH₂-CH₂-COOH | | (lone pair) (acidic H) Curved Arrows: - From N: lone pair → H of -COOH - From O-H bond → O of -COOH Result: [Eletriptan-NH⁺] + [⁻OOC-CH₂-CH₂-COOH] | | (protonated) (succinate anion) ``` --- ### **Visual (Text Representation):** ```plaintext Eletriptan Succinic acid N: HOOC-CH2-CH2-COOH / \ Step 1: Lone pair on N attacks H of -COOH O-H bond breaks, electrons go to O Eletriptan-NH⁺ ⁻OOC-CH2-CH2-COOH (protonated) (succinate anion) ``` --- ## **Final Product (Space-Filling Representation)** - Draw eletriptan with an extra H on the N (NH⁺ group). - Draw succinic acid as a monoanion (one COO⁻, one COOH). - Place them close to show ionic interaction. --- ## **Summary Table** | Reactant | Role | Product Form | |-------------------|-----------|-------------------| | Eletriptan (amine)| Base | Eletriptan-NH⁺ | | Succinic acid | Acid | Succinic monoanion| --- ## **Key Points** - **Curved arrows:** - From N lone pair to H of -COOH - From O-H bond to O (forms COO⁻) - **Final product:** - Eletriptan-NH⁺ (protonated amine) - Succinic acid as monoanion (⁻OOC-CH₂-CH₂-COOH) --- If you need a **hand-drawn diagram with arrows**, let me know! I can provide a sketched-out version.