Consider a planar wing ( i . e . , no geometric twist ) which has a NACA 0 0 1 2 section and an aspect ratio of 7 . 0 . Use a 4 term series to represent the load distribution for a taper ration of 0 . 4 .
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Consider a planar wing ( i . e . , no geometric twist ) which has a NACA 0 0 1 2 section and an aspect ratio of 7 . 0 . Use a 4 term series to represent the load distribution for a taper ration of 0 . 4 .
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Asked by: manish kumar
Created at: 2025-12-13 09:27:43
Asked by: manish kumar
Created at: 2025-12-13 09:27:43
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# Load Distribution on a Planar Wing (NACA 0012, AR = 7., Taper Ratio = .4)
This outlines the process to represent the lift distribution across a planar (untwisted) wing with the specified characteristics using a four-term series.
## Wing Characteristics
- **Airfoil:** NACA 0012 (symmetric, linear lift curve)
- **Aspect Ratio (AR):** 7.
- **Taper Ratio (\(\lambda\)):** .4
- **Geometric Twist:** None (planar wing)
## Series Representation: Lifting-Line Theory
The spanwise circulation (or load) distribution can be represented as a Fourier sine series:
\[
\theta = \cos^{-1}\left(\frac{2y}{b}\right)
\]
\[
\frac{c(y) \, C_l(\theta)}{4b} = \sum_{n=1}^{N} A_n \sin(n\theta)
\]
where:
- \(b\): wingspan
- \(y\): spanwise location, \( -b/2 \leq y \leq b/2 \)
- \(c(y)\): local chord at \(y\)
- \(C_l(\theta)\): local section lift coefficient
- \(A_n\): series coefficients
For a **4-term series** (\(N = 4\)):
\[
C_l(\theta) = \sum_{n=1}^4 A_n \sin(n\theta)
\]
## Chord Distribution (Tapered Wing)
The chord at any spanwise position is:
\[
c(y) = c_{root} \left[1 - (1 - \lambda)\frac{2|y|}{b}\right]
\]
or, in terms of \(\theta\):
\[
c(\theta) = c_{root} \left[1 - (1 - \lambda)\sin\theta\right]
\]
where:
- \(\lambda = .4\): taper ratio
## Boundary Conditions
For a planar, untwisted wing with a symmetric airfoil, the angle of attack is constant and there is no geometric twist.
## Discretization
Select four values of \(\theta\) for \(N = 4\):
\[
\theta_j = \frac{j\pi}{N+1}, \quad j = 1, 2, 3, 4
\]
\[
\theta_1 = .2\pi \quad
\theta_2 = .4\pi \quad
\theta_3 = .6\pi \quad
\theta_4 = .8\pi
\]
## Solving for Series Coefficients (\(A_n\))
The coefficients \(A_n\) are found by solving the following system at the collocation points (\(\theta_j\)):
\[
\alpha_ = \sum_{n=1}^4 A_n \sin(n\theta_j) \left[\frac{4b}{c(\theta_j) a_} + n\frac{\sin\theta_j}{\sin(n\theta_j)}\right]
\]
Where:
- \(\alpha_\): geometric angle of attack (assumed constant)
- \(a_\): sectional lift curve slope (for NACA 0012, typically \(2\pi\))
- \(c(\theta_j)\): chord at \(\theta_j\)
- \(b\): wingspan
Set up the 4 equations (one at each \(\theta_j\)), and solve for \(A_1, A_2, A_3, A_4\).
## Summary of Procedure
1. **Express the chord distribution:**
\[
c(\theta) = c_{root} \left[1 - .6 \sin\theta\right]
\]
2. **Choose collocation points:**
\(\theta_j = .2\pi, .4\pi, .6\pi, .8\pi\)
3. **Set up a system of 4 equations:**
For each \(\theta_j\), use the lifting-line equation to relate the \(A_n\).
4. **Solve for \(A_1, A_2, A_3, A_4\):**
This gives the spanwise loading as a 4-term series.
## Final Series Form
The load distribution is:
\[
C_l(\theta) = A_1 \sin\theta + A_2 \sin(2\theta) + A_3 \sin(3\theta) + A_4 \sin(4\theta)
\]
The coefficients \(A_n\) depend on the wing planform and can be determined numerically from the above system.
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**Note:**
- This method gives an approximate spanwise load distribution for a tapered, untwisted wing using a 4-term Fourier sine series.
- For actual values of \(A_n\), plug in the numerical values for \(c(\theta_j)\), \(\lambda\), \(AR\), and solve the linear system.
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