Blood perfuses a region of tissue at a flow rate of 0.35 mL min-1 cm-3 of tissue. The pO2 of the entering blood is 95 mmHg and exiting pO2 of the blood is 20 mmHg. Calculate the metabolic oxygen consumption rate of this tissue in micomolar/sec.
Question:
Blood perfuses a region of tissue at a flow rate of 0.35 mL min-1 cm-3 of tissue. The pO2 of the entering blood is 95 mmHg and exiting pO2 of the blood is 20 mmHg. Calculate the metabolic oxygen consumption rate of this tissue in micomolar/sec.
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Asked by: Nikita Gaikwad
Created at: 2025-06-19 15:24:19
Asked by: Nikita Gaikwad
Created at: 2025-06-19 15:24:19
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Let's break down the problem step by step:
**Given:**
- Blood flow rate \( Q = 0.35 \) mL/min/cm³ tissue
- \( pO_2 \) of **entering blood** = 95 mmHg
- \( pO_2 \) of **exiting blood** = 20 mmHg
- **Want:** Oxygen consumption rate in **μM/sec**
---
### **Step 1: Find the amount of O\(_2\) delivered and removed (using pO\(_2\) difference)**
We will use the oxygen content difference (not just \( pO_2 \)) to calculate the amount consumed.
**Assumption:** Most O\(_2\) in blood is bound to hemoglobin. However, unless hemoglobin content is given, we can do the calculation using **dissolved O\(_2\) only** (if you want the full calculation with Hb, more data is needed).
Let's proceed with **dissolved O\(_2\)** (if you need with hemoglobin, please clarify!).
The concentration of dissolved O\(_2\) in plasma is:
\[
[\mathrm{O}_2]_{\text{dissolved}} = \alpha \cdot pO_2
\]
where
- \( \alpha \) (solubility coefficient) ≈ **0.0031 mL O\(_2\) / 100 mL blood / mmHg**
Thus,
- [O\(_2\)] in entering blood: \( 0.0031 \times 95 = 0.2945 \) mL O\(_2\) / 100 mL blood
- [O\(_2\)] in exiting blood: \( 0.0031 \times 20 = 0.062 \) mL O\(_2\) / 100 mL blood
Difference:
\[
\Delta [\mathrm{O}_2] = 0.2945 - 0.062 = 0.2325 \text{ mL O}_2 / 100 \text{ mL blood}
\]
---
### **Step 2: Calculate total oxygen extracted per minute per cm³ tissue**
Blood flow per minute per cm³ = \( Q = 0.35 \) mL/min/cm³
Per min, O\(_2\) extracted:
\[
\text{O}_2\, \text{extracted/min} = Q \times \Delta [\mathrm{O}_2]
\]
But, units:
- Q is in mL blood/min/cm³
- Δ[O2] is in mL O2/100 mL blood
So,
\[
\text{O}_2\, \text{extracted/min} = 0.35\, \text{mL blood/min/cm}^3 \times 0.2325\, \frac{\text{mL O}_2}{100\, \text{mL blood}}
\]
\[
= 0.35 \times 0.002325\, \text{mL O}_2 / \text{min} / \text{cm}^3
\]
\[
= 0.00081375\, \text{mL O}_2 / \text{min} / \text{cm}^3
\]
---
### **Step 3: Convert mL O\(_2\) to μmol O\(_2\)**
- 1 mole of gas at STP = **22.4 L**
- 1 mL O\(_2\) = \( 1/22400 \) mol = **44.64 μmol**
So,
\[
0.00081375\, \text{mL} \times 44.64\, \frac{\mu\text{mol}}{\text{mL}}
= 0.03632\, \mu\text{mol/min/cm}^3
\]
---
### **Step 4: Convert from μmol/min/cm³ to μM/sec**
- 1 cm³ = 1 mL = 1 × 10⁻³ L
- μM = μmol/L
So, per liter:
\[
0.03632\, \mu\text{mol} / \text{min} / 1 \text{ mL} = 36.32\, \mu\text{mol} / \text{min} / \text{L}
\]
But we want per second:
\[
36.32\, \mu\text{mol} / \text{min} / \text{L} \div 60 = 0.605\, \mu\text{mol} / \text{sec} / \text{L}
\]
So, the **metabolic O\(_2\) consumption rate** is:
\[
\boxed{0.605\, \mu\text{M/sec}}
\]
---
## **Final Answer**
\[
\boxed{0.61\, \mu\text{M/sec}}
\]
(Rounded to two significant digits)
---
### **Summary of Steps**
1. **Calculate O\(_2\) content difference**: Δ[O2] = 0.2325 mL O2 / 100 mL blood
2. **Calculate O\(_2\) extracted**: \( Q \times \Delta[O_2] \)
3. **Convert to μmol/min**: \( 0.00081375\, \text{mL O}_2 \) × 44.64 μmol/mL
4. **Convert to μM/sec**: scale up to per liter, divide by 60.
**Assumptions:** Only dissolved O\(_2\) considered. If you want to include hemoglobin-bound O\(_2\), you'll need Hb concentration and O\(_2\) saturation curves. For most tissues, bound O\(_2\) dominates. This answer is for dissolved O\(_2\) only. Let me know if you want the calculation including hemoglobin!
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